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3 years ago

Please help # 36,38 and 39 ASAP.Thanks:)

Mathematics

1 answer:

Rzqust [24]3 years ago

4 0

36 is B
37 is H
Do not quote me on this, but I think the first inequality x= any number over 15
And the second one is r=4

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What’s the answer in neeeeeeeeed it………

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Answer:

10x

Step-by-step explanation:

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3 years ago

Find the general solution to 3y′′+12y=0. Give your answer as y=... . In your answer, use c1 and c2 to denote arbitrary constants

lozanna [386]

Answer:

$y(x)=c_1e^{2ix}+c_2e^{-2ix}$

Step-by-step explanation:

You have the following differential equation:

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In order to find the solution to the equation, you can use the method of the characteristic polynomial.

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3 years ago

Write the following decimal number in its equivalent fraction form. Show all work for full credit. 0.888

STALIN [3.7K]

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6 0

4 years ago

Read 2 more answers

Nina thought of a number. She called her number y. She added 14 to her number, divided the result by 6, and she got 12. What was

Leto [7]

Y=58
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4 years ago

Read 2 more answers

David’s bank offers a 36-month Certificate of Deposit (CD) with an APR of 2.25%. Use the compound interest formula to answer the

tamaranim1 [39]

Using compound interest, it is found that:

a) A(8) = 2389.66

b) t = 31.15

c) P = 1870.85

Compound interest:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

A(t) is the amount of money after t years.
P is the principal(the initial sum of money).
r is the interest rate(as a decimal value).
n is the number of times that interest is compounded per year.
t is the time in years for which the money is invested or borrowed.

In this problem:

The APR is of 2.25%, hence $r = 0.0225$ .

No information about the number of compounding per year, hence $n = 1$ .

Item a:

$P = 2000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$A(8) = 2000\left(1 + \frac{0.0225}{1}\right)^{8}$

$A(8) = 2389.66$

Item b:

$A(t) = 4000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$4000 = 2000\left(1 + \frac{0.0225}{1}\right)^{t}$

$(1.0225)^t = 2$

$\log{(1.0225)^t} = \log{2}$

$t\log{1.0225} = \log{2}$

$t = \frac{\log{2}}{\log{1.0225}}$

$t = 31.15$

Item c:

$A(3) = 2000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$2000 = P\left(1 + \frac{0.0225}{1}\right)^{3}$

$P = \frac{2000}{(1.0225)^3}$

$P = 1870.85$

A similar problem is given at brainly.com/question/24850750

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2 years ago