it hasn't been specified which ticket the question's is asking but I'm guessing the price of the adult ones so $30.00
altogether that's two adults and 3 children who all paid a total of $105.00
let's simplify that to algebra
children tickets = c adults tickets = a
3c + 2a = $105.00
we know that 1c is 0.5a because each child ticket is half of an adults one <em>as stated in the question</em>
so in terms of (adults) a: half of 3 meaning 3×0.5= $1.5 meaning 1.5a
so now <em>3c = 1.5a</em>
so we can substitute and have like terms
meaning 1.5a + 2a= $105
3.5a =$105.00
divide by 3.5 on both sides to get a by itself thus the value of a:
a = $30
so each adult tickets cost $30
Answer:
36.9 m
Step-by-step explanation:
h(t) = -4.9t² + 25t + 6
At t = 3:
h(3) = -4.9(3)² + 25(3) + 6
h(3) = -44.1 + 75 + 6
h(3) = 36.9
After 3 seconds, the ball will have a height of 36.9 meters.
Answer:
Step-by-step explanation:
5(y+4) = 4(y+5)
5y+20 = 4y + 20
5y = 4y
y=0
He could be 40321 years old.
If you divide 40321 by any odd or even number between 1 and 9, the remainder is 1.
I got this number by doing (2*3*4*5*6*7*8) + 1
