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2 years ago

Find value of the variables#7

Mathematics

1 answer:

RideAnS [48]2 years ago

3 0

Because of exterior angles theorem, y=39+65, so y=104
x and y are a linear pair, so they add up to 180. x=180-104, x=76
all angles in a triangle add up to 180, so 21+104+z=180. therefore, z=55

y=104
x=76
z=55

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Arrange the following measurements from smallest to largest

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Answer: 1,296 m iles

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

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Step-by-step explanation:

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wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

$\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}$

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

$\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\ \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}$

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

$\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\ \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\ \\ \therefore E_1\equiv E_2=55580ft \end{gathered}$

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4 months ago

Define four symbolic constants that represent integer 25 in decimal, binary, octal, and hexadecimal formats

stealth61 [152]

Answer:

1) Decimal $25= (25)_{10}$

2) Binary $25= (11001)_2$

3) Octal $25= (31)_8$

4) Hexadecimal $25= (19)_{16}$

Step-by-step explanation:

Given : Integer is 25

To find : Represent integer in decimal, binary, octal, and hexadecimal formats.

Solution :

1) Integer into decimal - To convert into decimal the base goes to 10.

So, $25= (25)_{10}$

2) Integer into binary - To convert into binary the base goes to 2, it form in 0 and 1 and we divide integer by 2.

Divide 25 by 2 and note down the remainders.

2 | 25

2 | 12 R=1 ←

2 | 6 R=0 ↑

2 | 3 R=0 ↑

2 | 1 → R=1 ↑

So, $25= (11001)_2$

3) Integer into octal - To convert into octal the base goes to 8 and we divide integer by 8.

Divide 25 by 8 and note down the remainders.

8 | 25

| 3 → R=1

So, $25= (31)_8$

4) Integer into hexadecimal - To convert into hexadecimal the base goes to 16 and we divide integer by 16.

Divide 25 by 16 and note down the remainders.

16 | 25

| 1 → R=9

So, $25= (19)_{16}$

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