Question

Solve by completing the square 9x^ - 18 x +93= -6

Answer 1

$9x^2 - 18 x + 93= -6$

take away 93 from both sides
$9x^2 - 18 x = - 99$

Divide by 9 through
$x^2 - 2 x = - 11$

Add (b/2)^2 to form perfect square
$x^2 - 2 x + ( \frac{2}{2} )^2 = - 11 + ( \frac{2}{2} )^2$

Form perfect square
$(x - 1)^2 = - 10$

Square root both sides to find x
$x - 1 = \pm \sqrt{-10}$

add 1 on both sides
$x = 1+ i\sqrt{10} \ or \ 1- i\sqrt{10}$