Answer:
The possible sequence of the decapeptide is Met-Val-Lys-Tyr-Thr-Trp-Ala-Arg-Pro-Phe.
Explanation:
The cyanogen bromide cleaves the carboxyl end of Met (methionine and non-peptide). Trypsin cleaves on the C-terminal of Arg and Lys, however, not on the N-terminal of Pro, which signifies that Lys is the last amino acid in T2. Hence, Met-Val-Lys----. The middle part of the sequence can be predicted from the digestion done by chymotrypsin.
The chymotrypsin cleaves on the C terminal of Phe, Trp, Tyr, however, not on the N side of Pro. CT3 exhibit Lys, Met, Tyr, Val, as Met-Val and Tyr are the initial three amino acids, therefore, Tyr must be the fourth one. Now the sequence will be Met-Val-Lys-Tyr...
CT1 possesses Ala, Arg, Phe, Pro, as chymotrypsin cleaves the C side of the Phe, thus, the last amino acid should be Phe. Also, CT1 has Ala as the first amino acid. Also, trypsin does not cleave on the N-end of Pro. Thus, the sequence of CT1 strands will be Ala-Arg-Pro-Phe.
In CT2, chymotrypsin cleaves on the C-side of trp. Thus, the sequence of CT2 strands as Thr-Trp is found in the middle. Thus, the whole sequence of the decapeptide strand will be:
Met-Val-Lys-Tyr-Thr-Trp-Ala-Arg-Pro-Phe.
