Answer:
The given expanded sum of the series is 
Step-by-step explanation:
Given problem can be written as
To find their sums:
Now expanding the series
That is put n=5,6,7,8,9 in the given summation
![\sum\limits_{n=5}^{9}3n+2=[3(5)+2]+[3(6)+2]+[3(7)+2]+[3(8)+2]+[3(9)+2]](https://tex.z-dn.net/?f=%5Csum%5Climits_%7Bn%3D5%7D%5E%7B9%7D3n%2B2%3D%5B3%285%29%2B2%5D%2B%5B3%286%29%2B2%5D%2B%5B3%287%29%2B2%5D%2B%5B3%288%29%2B2%5D%2B%5B3%289%29%2B2%5D)
![=[15+2]+[18+2]+[21+2]+[24+2]+[27+2]](https://tex.z-dn.net/?f=%3D%5B15%2B2%5D%2B%5B18%2B2%5D%2B%5B21%2B2%5D%2B%5B24%2B2%5D%2B%5B27%2B2%5D)
(adding the terms)
Therefore
Therefore the given sum of the series is
The given expanded sum of the series is
J + -2 = -22
Adding a negative number changes the equation to subtract ruin:
J - 2 = -22
Now add 2 to both sides to get the answer:
J = -20
Answer:
4.24
Step-by-step explanation:
First, let's set up the equation: 
Next, clear the fraction by multiplying both sides by 2:
Then, subtract 2 from both sides: 
Finally, take a square root of both sides and round: 
(Rounded to the nearest hundredth) 4.24
Answer:
49849 x 83582 = 4166479118
96395 x 9384 = 904570680
8994 x 9692 = 87169848
4048 x 2048 = 8290304
Hope this helped
Step-by-step explanation:
Please mark me as brainliest :D
