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sladkih [1.3K]
3 years ago
7

Does soil without nitrogen decrease the weight of worms when compared to soil with nitrogen? The weights of 14 randomly selected

worms are taken, 7 in soil with nitrogen, and 7 in soil without nitrogen. The mean weights of worms in soil without nitrogen was 35.3 micrograms, while the mean weights of worms in soil with nitrogen was 36.3 micrograms. A researcher randomized the data over 100 trials, and the difference of means for each trial is shown in the dot plot below. What can the researcher conclude from this study?
a. The difference in weights is not significant because an original difference of means of –1 is very likely
b. The difference in weights is significant because an original difference of means of –1 is not very likely
c. The difference in weights is significant because an original difference of means of –1 is very likely
d. The difference in weights is not significant because an original difference of means of –1 is not very likely

Mathematics
1 answer:
zhuklara [117]3 years ago
4 0
It Would be choice B. Hope it helps!

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A wise man once said "300 reduced by 3 times my age is 138"
Nonamiya [84]
The equation is 138=300-3x
now solve by first subtracting 300 from each side: -162=-3x
divide each side by -3: x=54
The wise man is 54 years old
7 0
3 years ago
Add [1/-4 3/5] [-2/6 -2/4]
brilliants [131]

Answer:

​25/138

Step-by-step explanation:

1 Convert 4\frac{3}{5}4

​5

​

​3

​​  to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

​c

​

​b

​​ =

​c

​

​ac+b

​​ .

\frac{1}{-(\frac{4\times 5+3}{5})}(-\frac{2}{6}-\frac{2}{4})

​−(

​5

​

​4×5+3

​​ )

​

​1

​​ (−

​6

​

​2

​​ −

​4

​

​2

​​ )

2 Simplify  4\times 54×5  to  2020.

\frac{1}{-(\frac{20+3}{5})}(-\frac{2}{6}-\frac{2}{4})

​−(

​5

​

​20+3

​​ )

​

​1

​​ (−

​6

​

​2

​​ −

​4

​

​2

​​ )

3 Simplify  20+320+3  to  2323.

\frac{1}{-(\frac{23}{5})}(-\frac{2}{6}-\frac{2}{4})

​−(

​5

​

​23

​​ )

​

​1

​​ (−

​6

​

​2

​​ −

​4

​

​2

​​ )

4 Simplify  \frac{2}{6}

​6

​

​2

​​   to  \frac{1}{3}

​3

​

​1

​​ .

\frac{1}{-(\frac{23}{5})}(-\frac{1}{3}-\frac{2}{4})

​−(

​5

​

​23

​​ )

​

​1

​​ (−

​3

​

​1

​​ −

​4

​

​2

​​ )

5 Simplify  \frac{2}{4}

​4

​

​2

​​   to  \frac{1}{2}

​2

​

​1

​​ .

\frac{1}{-(\frac{23}{5})}(-\frac{1}{3}-\frac{1}{2})

​−(

​5

​

​23

​​ )

​

​1

​​ (−

​3

​

​1

​​ −

​2

​

​1

​​ )

6 Find the Least Common Denominator (LCD) of \frac{1}{3},\frac{1}{2}

​3

​

​1

​​ ,

​2

​

​1

​​ . In other words, find the Least Common Multiple (LCM) of 3,23,2.

LCD = 66

7 Make the denominators the same as the LCD.

-\frac{1\times 2}{3\times 2}-\frac{1\times 3}{2\times 3}−

​3×2

​

​1×2

​​ −

​2×3

​

​1×3

​​

8 Simplify. Denominators are now the same.

-\frac{2}{6}-\frac{3}{6}−

​6

​

​2

​​ −

​6

​

​3

​​

9 Join the denominators.

\frac{-2-3}{6}

​6

​

​−2−3

​​

10 Simplify  -\frac{1}{3}-\frac{1}{2}−

​3

​

​1

​​ −

​2

​

​1

​​   to  -\frac{5}{6}−

​6

​

​5

​​ .

\frac{1}{-(\frac{23}{5})}\times \frac{-5}{6}

​−(

​5

​

​23

​​ )

​

​1

​​ ×

​6

​

​−5

​​

11 Move the negative sign to the left.

-\frac{1}{\frac{23}{5}}\times \frac{-5}{6}−

​

​5

​

​23

​​

​

​1

​​ ×

​6

​

​−5

​​

12 Invert and multiply.

-\frac{5}{23}\times \frac{-5}{6}−

​23

​

​5

​​ ×

​6

​

​−5

​​

13 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}

​b

​

​a

​​ ×

​d

​

​c

​​ =

​bd

​

​ac

​​ .

-\frac{5\times -5}{23\times 6}−

​23×6

​

​5×−5

​​

14 Simplify  5\times -55×−5  to  -25−25.

-\frac{-25}{23\times 6}−

​23×6

​

​−25

​​

15 Simplify  23\times 623×6  to  138138.

-\frac{-25}{138}−

​138

​

​−25

​​

16 Move the negative sign to the left.

-(-\frac{25}{138})−(−

​138

​

​25

​​ )

17 Remove parentheses.

\frac{25}{138}

​138

​

​25

​​

7 0
3 years ago
Kendra had twice as much money as kareem. Kendra later spent $8 and kareem earned $6. By then,the two had the same amount of mon
Svet_ta [14]

Answer:

x = 2y

x - 8 = y + 6

replace x by 2y in the second equation

2y - 8 = y + 6

y - 8 = 6

y = 14

x = 2*14 = 28

Kendra had $28 and Kareem had $14.

6 0
3 years ago
Please can some explain how to identify angles that on the same segment? ​
sp2606 [1]

Step-by-step explanation:

Angles in the same segment. The angles at the circumference subtended by the same arc are equal. More simply, angles in the same segment are equal.

Picture 1  a° = a°  they are the same

Picture 2  p= 52°  q= 40° Angles in the same segment are equal. if they ask you to calculate you just show both angles p= 52 and q=40.

Picture 3 + 4  Let the obtuse angle MOQ = 2x.  

Using the circle theorem, the angle at the centre is twice   the angle at the circumference.

Therefore picture 4 tells us and proves;

Angle MNQ = x and angle MPQ = x.

Picture 5

A cyclic quadrilateral is a quadrilateral drawn inside a circle. Every corner of the quadrilateral must touch the circumference of the circle.

The second shape is not a cyclic quadrilateral. One corner does not touch the circumference.

Picture 6

The opposite angles in a cyclic quadrilateral add up to 180°.

a + c = 180°

b + d = 180°

Picture 7

Example

Calculate the angles a and b.

The opposite angles in a cyclic quadrilateral add up to 180°.

This is a picture that couldn't be added but has a quadrilateral occupying half the triangle consisting of 3 arcs the middle one was 140 and proved part of one triangle. The x (a) missing angle showed below a = 180-60 = 120 °

So hopefully this will help you remember the format here for quadrilateral shapes within a circle.

b = 180 - 140 = 40°

a = 180 - 60 = 120°

8 0
3 years ago
X/3 = 2,how to calculate x? <br> please help me
liq [111]

Given:

  • \sf  \dfrac{x}{3}  = 2

Solution:

\longrightarrow \sf \dfrac{x}{3}  = 2 \\  \\  \sf\longrightarrow x = 3 \times 2 \\  \\  \longrightarrow   {\underline{\boxed{ \pink {\sf{x = 6}}} }}\\  \\

4 0
2 years ago
Read 2 more answers
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