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Sever21 [200]
3 years ago
12

Find m∠PQW if m∠WQR = 130°, m∠PQR = 16x, and m∠PQW = 3x.

Mathematics
1 answer:
V125BC [204]3 years ago
5 0

Answer:

m\angle PQW=30^o

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m\angle PQR=m\angle PQW+m\angle WQR ---> by addition angle postulate

substitute the given values

16x=3x+130\o

solve for x

16x-3x=130^o

13x=130^o

x=10^o

Find the measure of angle PQW

m\angle PQW=3x

substitute the value of x

m\angle PQW=3(10^o)=30^o

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Tortileni

Step-by-step explanation:

5 0
3 years ago
State the slope-intercept form of the equation for the graph with the points 3,0 and 0,-1
Dvinal [7]

Answer:

The answer is y=1/3x-1

Step-by-step explanation:

m=1/3

y-y=m(x-x1)

y-(-1)=1/3(x-0)

y+1=1/3x-0

-1 -1

y=1/3x-1

6 0
3 years ago
I need help please help
vesna_86 [32]

Answer:

C. (x-2)^2=7

Step-by-step explanation:

What you have to do first is to get rid of the 3 in the x^2 so you will divide 3 by the whole thing to get x^2-4x=3.

You will then divide -4 by 2 and then square the answer to get 4.

You will then add the 4 into the end of the equation and to the 3 to get x^2-4x+4=7.

You will then make into a perfect square (x-2)^2=7 and that is your answer.

5 0
3 years ago
Solve for n. (7^2)^4 = n^8
enyata [817]
7^2x4 = n^8
7^8 = n^8
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4 0
2 years ago
P and W are twice-differentiable functions with P(7)=2(W(7)). The line y=9+2.5(x-7) is tangent to the graph of P at x=7. The lin
fiasKO [112]

Using the product rule, we have

m(x) = x W(x) \implies m'(x) = xW'(x) + W(x)

so that

m'(7) = 7W'(7) + W(7)

The equation of the tangent line to <em>W(x)</em> at <em>x</em> = 7 has all the information we need to determine <em>m'</em> (7).

When <em>x</em> = 7, the tangent line intersects with the graph of <em>W(x)</em>, and

<em>y</em> = 4.5 + 2 (7 - 7)   ==>   <em>y</em> = 4.5

means that this intersection occurs at the point (7, 4.5), and this in turn means <em>W</em> (7) = 4.5.

The slope of this tangent line is 2, so <em>W'</em> (7) = 2.

Then

m'(7) = 7\cdot2 + 4.5 = \boxed{18.5}

4 0
2 years ago
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