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3 years ago

Help plz plz I only have 30 minutes

Mathematics

2 answers:

natulia [17]3 years ago

5 0

Answer:

50% increase in weight

Step-by-step explanation:

First, write the situation out in an equation:

7/100=10.5/x

If we find the difference assuming 7 is 100% and 10.5 is x%, then we can subtract to find the difference.

Solve this equation for x. The answer would look like this:

7/100=10.5/150

Then, since 150% - 100% is 50%, the answer is a 50% increase.

Hope this helps! Please mark brainliest! :)

Alex_Xolod [135]3 years ago

3 0

Answer:3.5 tons

Step-by-step explanation:

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The graph of f(x) = 2x + 1 is shown below. Explain how to find the average rate of change between x = 0 and x = 3.

Irina-Kira [14]

<span><span>The average rate of change formula is basically the slope formula, where you plug in: f(b)-f(a)/b-a. Then plug in the numbers. [f(0)=1,f(3)=7)]. So, 7-1/3-0. 6/3 is 2 so the average rate of change is 2. And that makes sense because the average rate of change is always the slope, and the slope is 2.</span></span>

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3 years ago

PLZZZZ HELP GIVE ALL POINTS I HAVE

Amanda [17]

Answer:

1/4

Step-by-step explanation:

3 0

3 years ago

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Use the rule of 78 to find the finance charge refund if the Finance charge was $476 on a 12 month payment plan and the loan was

Lelu [443]

Answer:

finance charge refund is $91.53

Step-by-step explanation:

given data

finance charge F = $476

time t = 12 month

no of payment n = 5

to find out

finance charge refund

solution

we will apply here finance charge refund formula that is

finance charge refund = F × $\frac{n * (n+1)}{t* (t+1)}$

put here value we get

finance charge refund = 476 × $\frac{5 * (5+1)}{12* (12+1)}$

finance charge refund = 476 × $\frac{5 * (6)}{12 * (13)}$

finance charge refund = 476 × $\frac{30}{156}$

finance charge refund = 476 × 0.1923

finance charge refund = 91.53

so finance charge refund is $91.53

4 0

3 years ago

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago

Help ASAP if u can ?

scoundrel [369]

Answer:

7 and -8

Step-by-step explanation:

A coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression (e.g. 4 in 4x).

8 0

3 years ago