Well 9x40 would be the solution, so what is 9x40? That will be your answer.
Answer:D
Step-by-step explanation:
(3x^3 - 5x^2 + 4x - 9)-(7x^3 - 8x^2 - 5x + 10)
open brackets
3x^3 - 5x^2 + 4x - 9 - 7x^3 + 8x^2 +5x - 10
Collect like terms
3x^3-7x^3-5x^2+8x^2+4x+5x-9-10
-4x^3+3x^2+9x-19
Answer:
Between 4 and 5
Step-by-step explanation:
The closest square numbers are 16 and 25, so it’s in between 4 and 5
Answer:
4x^2 + 8x + 4
4(x^2 + 2x + 1) - remove GCF of 4
4(x + 1)(x + 1) - factor
4(x + 1)^2 - collect like terms
Step-by-step explanation:
Then also expand it out by distributing:
21x^3 + 35x²
Form 1:
21x^3 + 35x² - unfactored
Form 2:
7x²(3x + 5) - factored with GCF of 7x² brought to the front
Update:
You could also multiply two binomials and make a quadratic.
Example:
(7x + 2)(3x + 5)
7x(3x + 5) + 2(3x + 5)
= 21x² + 35x + 6x + 10
= 21x² + 41x + 10
Answer:
Area of equilateral triangle = 81√3 cm²
Step-by-step explanation:
Given:
Perimeter of an equilateral triangle = 54 cm
Find:
Area of equilateral triangle
Computation:
Perimeter of an equilateral triangle = 3 x Side
54 = 3 x Side
Side of equilateral triangle = 54 / 3
Side of equilateral triangle = 18 cm
Area of equilateral triangle = [√3/4]side²
Area of equilateral triangle = [√3/4][18]²
Area of equilateral triangle = [√3/4][324]
Area of equilateral triangle = [√3][81]
Area of equilateral triangle = 81√3 cm²
