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3 years ago

15

the cost of printing 200 business cards is $23. The cost of printing 500 business cards at the same business is $35. Write and s

olve a linear equation to find the cost for printing 700 business cards.

1 answer:

lana66690 [7]3 years ago

4 0

It should be $80.50.
Divide 23 by 200,
Times that number by 700,
Wella! there's your answer.
~Glad to help.

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Which relationship would most likely have a positive correlation?

tiny-mole [99]

Answer:

C.

Step-by-step explanation:

The only thing to do here is just check all of the answers.

A makes no sense, as the number of keys on a keyboard doesn't affect the amount of memory in a computer at all (no correlation).

B makes a bit more sense, but it's still wrong. If a train travels faster, it gets places quicker, or the time goes down. If (If one goes up, the other goes down) is true, then you have negative correlation.

C makes the most sense, as if there's more people at a game, then those more people will probably buy more hot dogs. If (If one goes up, so does the other) is true, then you have positive correlation, which is what we want.

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3 years ago

Which of the following is in the solution set of y< 8 x− 3? Select one: (7, 46) (7, 60) (10, 89) (9, 82)

navik [9.2K]

Answer:

(7, 46)

Step-by-step explanation:

The offered answer choices have x-values of 7, 9, 10. The corresponding upper limit of y-value is ...

x=7 : y < 8·7 -3 = 53 . . . . . 46 is in the solution set, 60 is not

x=9 : y < 8·9 -3 = 69 . . . . 82 is not in the solution set

x=10 : y < 8·10 -3 = 77 . . . . 89 is not in the solution set

Of the choices offered, only (7, 46) is in the solution set.

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3 years ago

One light-year equals 5.9 x 1012 miles. How many light-years are in 6.79

inna [77]

Option B

The number of light years in $6.79 \times 10^{16}$ miles is 11508 light years

<em><u>Solution:</u></em>

Given that,

One light-year equals 5.9 x 10^12 miles

Therefore,

$1 \text{ light year } = 5.9 \times 10^{12} \text{ miles }$

To find: Number of light years in $6.79 \times 10^{16}$ miles

Let "x" be the number of light years in $6.79 \times 10^{16}$ miles

Then number of light years in $6.79 \times 10^{16}$ miles can be found by dividing $6.79 \times 10^{16}$ miles by miles in 1 light year

$\text{Number of light years in } 6.79 \times 10^{16} miles = \frac{6.79 \times 10^{16}}{5.9 \times 10^{12}}\\\\\text{Use the law of exponent }\\\\\frac{a^m}{a^n} = a^{m-n}\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = \frac{6.79}{5.9} \times 10^{16-12}\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = 1.1508 \times 10^4\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = 11508$

Thus number of light years in $6.79 \times 10^{16}$ miles is 11508 light years

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Answer:

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Because the text says that all types of dogs are found in even numbers, it would not matter if there was 6, 12, 18, ... amount of dogs.

When looking at this sample space, you can see that the chance of choosing a Yellow/F dog, is 1 in 6.

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