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3 years ago

Point P is located at (-3,5)

Mathematics

1 answer:

Naya [18.7K]3 years ago

5 0

Answer:

P' (- 7, - 5 )

Step-by-step explanation:

A translation of 3 units to the left means subtractin 3 from the x- coordinate with no change to the y- coordinate, thus

P(- 3, 5 ) → (- 3 - 4, 5 ) → (- 7, 5 )

Under a reflection in the x- axis

a point (x, y ) → (x, - y ), thus

(- 7, 5 ) → P'(- 7, - 5 )

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ASAP HELP, PLEASE HELP NEED IT FOR COLLEGE SCHOLARSHIP PLEASE HELP ASAP i really need it for college scholarship help ive to sub

sweet-ann [11.9K]

Answer:

I think it might be 30pi m or 94.2 m.

Step-by-step explanation: So you are finding the perimeter of the circle. You have a radius of 15, the perimeter for a circle is C=2pir. Now we can do C=2pi(15). The answer is 30pi or C=2 x 3.14 x 15= 94.2 Hope this helps.

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2 years ago

The graph of the function f is shown. f(0) = A) f(-1) B) f(2) C) f(3) D) f(4)

aalyn [17]

f(0) means x = 0

so when x = 0, y = -5

and when x = 4, f(4) is also equal -5 (y = -5)

so f(0) = f(4) = -5

Answer

D) f(4)

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2 years ago

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Graph the image of this triangle after a dilation with a scale factor of 2 centered at the origin. Use the polygon tool to graph

Nuetrik [128]

Answer:

(0,0), (-8,-8), (4,-8)

Step-by-step explanation:

(0 * 0, 0*0) = (0,0)

(-4*2,-4*2) = (-8,-8)

(2*2,-4*2) = (4,-8)

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3 years ago

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In the right triangle ?ABC, leg AC=6 cm and leg BC=8 cm. Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5. Find area of ?MN

Licemer1 [7]

Given : In Right triangle ABC, AC=6 cm, BC=8 cm.Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5.

To find : Area (ΔMNC)

Solution: In Δ ABC, right angled at C,

AC= 6 cm, BC= 8 cm

Using pythagoras theorem

AB² =AC²+ BC²

=6²+8²

= 36 + 64

→AB² =100

→AB² =10²

→AB =10

Also, AM:MN:NB=1:2.5:1.5

Then AM, MN, NB are k, 2.5 k, 1.5 k.

→2.5 k + k+1.5 k= 10

→ 5 k =10

Dividing both sides by 2, we get

→ k =2

MN=2.5×2=5 cm, NB=1.5×2=3 cm, AM=2 cm

As Δ ACB and ΔMNC are similar by SAS.

So when triangles are similar , their sides are proportional and ratio of their areas is equal to square of their corresponding sides.

$\frac{Ar(ACB)}{Ar(MNC)}=[\frac{10}{5}]^{2}$

$\frac{Ar(ACB)}{Ar(MNC)}=4$

But Area (ΔACB)=1/2×6×8= 24 cm²[ACB is a right angled triangle]

$\frac{24}{Ar(MNC)}=4$

→ Area(ΔMNC)=24÷4

→Area(ΔMNC)=6 cm²

4 0

3 years ago

If a+e = 11 a²-f=15 f+c=6 c×a-e=13 what is the value of the variables

CaHeK987 [17]

Answer:

a=4

c=5

e=7

f=1

Step-by-step explanation:

the simplest method would be to start with a(2)"squared" (being '4' as this will get you closest to 15. So 16 -1 (being 'c') = 15. now plug those into the other equations and work the other numbers out.

8 0

3 years ago