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3 years ago

I need help with an Algebra question. The question is in the picture. Thank you <3

Mathematics

1 answer:

olchik [2.2K]3 years ago

4 0

The domain is the set of allowed inputs, in this case t values. The smallest t value allowed is t = 0. The largest is t = 165. So that's why the domain is $0 \le t \le 165$

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The range is $0 \le H \le 40000$ since H = 0 is the smallest output of the function and H = 40,000 is the largest output. Like the domain, the range is the set of possible outputs of a function.

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Which of the following are solutions to the equation below?

sladkih [1.3K]

Answer:

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

Step-by-step explanation:

considering the equation

$2x^2\:-\:4x\:-\:3\:=\:x$

solving

$2x^2\:-\:4x\:-\:3\:=\:x$

$2x^2-4x-3-x=x-x$

$2x^2-5x-3=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

solving

$x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5+\sqrt{49}}{2\cdot \:2}$

$x=\frac{5+7}{4}$

$x=3$

also solving

$x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5-\sqrt{49}}{4}$

$x=-\frac{2}{4}$

$x=-\frac{1}{2}$

Therefore,

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

7 0

3 years ago

I need the answer pls

AleksAgata [21]

the answer is 32.........

8 0

2 years ago

Please help ill give brainliest

astra-53 [7]

Answer:

y = 7/8x + 1

Step-by-step explanation:

According to y = mx + b, whereas b is the y-intercept

so if b is positive, b has to be larger than 0

A non-proportional graph is a straight line that does not go through the origin so

The #1 and #4 are wrong because they are proportional

The #2 and #4 are wrong because they have negative y-intercept

3 0

2 years ago

Use the relationship between the angles in the figure to answer the question.

Brut [27]

Answer:

x + 49 + 28 = 180

Step-by-step explanation:

The angles on a straight line with x° are 28° and 49° respectively, side by side with x°. This is because, vertical angles are equal. Therefore, the angle vertically opposite 28° and 49° are equal to 28° and 49° respectively.

Therefore, since angles on a straight line is 180°, thus:

x + 49 + 28 = 180

6 0

3 years ago

Read 2 more answers

Write the standard form of the line that passes through the given points. include your work in your final answer. (-1, -3) and (

yan [13]

The standard form of a line passing through the points (-1, -3) and (2, 1) is 4x - 3y = 5.

The slope of the given line, m = (1 - (-3))/(2 - (-1)) = (1 + 3)/(2 + 1) = 4/3.

Computed using the formula for the slope of a line, m = (y₂ - y₁)/(x₂ - x₁), when a line passes through the points (x₁, y₁) and (x₂, y₂).

The point intercept form of a line is y - y₁ = m(x - x₁) when the line passes through the point (x₁, y₁) and has the slope m.

Thus, the given line in the point intercept form can be written as:

y - 1 = (4/3)(x - 2).

The standard form of a line is ax + by = c.

To convert the point intercept form to the standard form, we do as follows:

y - 1 = (4/3)(x - 2),

or, 3(y - 1) = 3(4/3)(x - 2) {Multiplying both sides by 3},

or, 3y - 3 = 4x - 8 {Simplifying},

or, 8 - 3 = 4x - 3y {Rearranging},

or, 4x - 3y = 5 {Rearranging and simplifying}.

Thus, the standard form of a line passing through the points (-1, -3) and (2, 1) is 4x - 3y = 5.

Learn more about equations of straight lines at

brainly.com/question/13763238

#SPJ4

6 0

2 years ago