The area of a rectangle is A=LW, the area of a square is A=S^2.
W=S-2 and L=2S-3
And we are told that the areas of each figure are the same.
S^2=LW, using L and W found above we have:
S^2=(2S-3)(S-2) perform indicated multiplication on right side
S^2=2S^2-4S-3S+6 combine like terms on right side
S^2=2S^2-7S+6 subtract S^2 from both sides
S^2-7S+6=0 factor:
S^2-S-6S+6=0
S(S-1)-6(S-1)=0
(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:
S=6 is the only valid value for S. Now we can find the dimensions of the rectangle...
W=S-2 and L=2S-3 given that S=6 in
W=4 in and L=9 in
So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.
D and E —> substitute the x or y of the point given into the functions to test if it is correct
Answer:
u = 5/4
Step-by-step explanation:
to evaluate for the value of u we would simply open the bracket and then evaluate for the value of u by collecting the like terms together.
solution
3=7(4 - 2u)-6u
3 = 28- 14u - 6u
collect the like terms
3 + 14u + 6u = 28
20u = 28 - 3
20u = 25
divide both sides by the coefficient of u which is 20
20u/20 = 25/20
u = 5/4
Ok first we can split it in two :
and
.
The derivative of
is 3.
For the first part, we use the chain rule :
![[f(g(x))]'=g'(x)f'(g(x))](https://tex.z-dn.net/?f=%5Bf%28g%28x%29%29%5D%27%3Dg%27%28x%29f%27%28g%28x%29%29)
hence
(since the derivative of the exponential is itself) hence
Answer: .34 ≤ x ≤ .81
Step-by-step explanation:
An inequality is writted like __ ≤ x ≤ ___
Since the humming bird can fly between .34 and .81 we use the the less than or equal to sign because it can fly max .81 mpm or less than that. with a minimum speed of .34 mpm.
