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3 years ago

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A toy shop purchases 125 identical stuffed animals for a total cost of $312.50 and sells them for $7 each.What is the percent ma

rkup?

2 answers:

ELEN [110]3 years ago

7 0

The number of identical stuffed animals given = 125.

The total purchase cost of the animals = $312.50.

Sellins price for each of them = $7.

So total selling price of 125 animals = $ $(125)(7)$ = $ $875$ .

Now we have to find percentage markup.

The formula to find percent mark up is

= $(\frac{(selling price -cost price)}{cost price})(100)$ %

= $(\frac{(875-312.50)}{312.50} )(100)$ %

= $(\frac{562.50}{312.50} )(100)$ %

= $(1.8)(100)$ %

= $180$ %

So we have got the required answer.

The percent mark up is 180%.

WITCHER [35]3 years ago

4 0

I feel like the answer is Answer:: 180%.

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2 years ago

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yes sure, i learned this before so

1. a. make a proportion here, of percentage. $\frac{225}{250} =\frac{x}{100}$ if you cross multiply and divide you get 90%.

1. b. obviously the empty seats would be 10%.

2. a. proportion again, $\frac{0.90}{6.00} =\frac{x}{100}$ cross multiply then divide you ge 15%

3. 30% in decimal form is 0.3. multiply it then to the total amount, so 0.3 x 15 = 4.5

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3 years ago

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A line intersects the points (6, -12) and (15, -3). What is the slope intercept equation for this line?

Korolek [52]

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3 years ago

Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)

zubka84 [21]

$\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } 
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This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

$\frac{ \sqrt{-49}}{7-2i-4-9i}$

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result:

$\frac{ \sqrt{-49} }{3-11i}$

Now, the $\sqrt{-49}$ must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to $\sqrt{49} \sqrt{-1}$
This means that we get the result 7i for the numerator.

$\frac{7i}{3-11i}$

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: $x^2 - y^2 =(x+y)(x-y)$
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

$\frac{7i (3+11i)}{(3-11i)(3+11i)}$

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how $(3-11i)(3+11i)= 3^2 -(11i)^2$ therefore, we can finally write:

$\frac{7i(3+11i)}{3^2 - (11i)^2 }$

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product $7i(3+11i) = 21i+77i^2$ .
You should know from your classes that i^2 = -1, thefore the numerator simplifies to $-77+21i$
You can do it as a curious thing, but simplifying yields the result:
$\frac{-77+21i}{130}$

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3 years ago