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shtirl [24]
3 years ago
8

2. Which of the following quadrilaterals have 2 pairs

Mathematics
1 answer:
Aneli [31]3 years ago
3 0

Answer: all of the above

Step-by-step explanation:

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Use the perfect square method <br> (3x + 3)^2 = 36
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Factor out the common term; 3

(3(x + 1))^2 = 36

Use the Multiplication Distributive Property; (xy)^a = x^ay^a

3^2(x + 1)^2 = 36

Simplify 3^2 to 9

9(x + 1)^2 = 36

Divide both sides by 9

(x + 1)^2 = 36/9

Simplify 36/9 to 4

(x + 1)^2 = 4

Take the square root of both sides

x + 1 = √4

Since 2 * 2 = 4, the square root of 2 is 2

x + 1 = 2

Break down the problem into these 2 equations

x + 1 = 2

x + 1 = -2

Solve the first equation; x + 1 = 2

x = 1

Solve the second equation; x + 1 = -2

x = -3

Collect all solutions;

<u>x = 1, -3</u>

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