2. Which of the following quadrilaterals have 2 pairs

The gas tank of Tyrell's truck holds 19.8 gallons. When the tank is empty, tyrell fills it with gas that costs 3.65 per gallon.

Dima020 [189]

3.65x19.8=$72.07 hit that thanks button and 5 star rating plz thankyou!!!!

7 0

3 years ago

2. After the American Revolution why was there a need to establish a stable banking system?

lora16 [44]

Answer:

Federalists wanted a

centralized banking

system and Alexander

Hamilton, as Secretary of

the Treasury, proposed a

national bank in 1789.

• Antifederalists, like

Thomas Jefferson,

opposed this plan.

– They favored a

decentralized banking

system in which states

established and

regulated banks within

their borders.

Step-by-step explanation:

5 0

3 years ago

Solve 2-3x=-x-8 i need help on this question i cant solve this

Nikitich [7]

Answer:

$x=5$

Step-by-step explanation:

We start by adding $3x$ to both sides, giving $2-3x+3x=-x+3x-8$ , which after simplifying gives $2=2x-8$ .

We then add $8$ to both sides, giving $2+8=2x-8+8$ , which after simplifying gives $10=2x$ .

We can then divide both sides by $2$ , giving $10/2=2x/2$ , which after simplifying gives $5=x$ , or $x=5$ . So, x is 5.

4 0

3 years ago

Tye bought a pizza for his friends for dinner. Tye ate 1/12 of the pizza. How much pizza is left?

bezimeni [28]

11/12
Because if you do 1-1/12 or 12/12-1/12 it will give you 11/12 you can check by adding 11/12+1/12

4 0

3 years ago

Assume that weights of adult females are normally distributed with a mean of 79 kg and a standard deviation of 22 kg. What perce

LenKa [72]

Answer:

14.28% of individual adult females have weights between 75 kg and 83 kg.

92.82% of the sample means are between 75 kg and 83 kg.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Assume that weights of adult females are normally distributed with a mean of 79 kg and a standard deviation of 22 kg. This means that $\mu = 79, \sigma = 22$ .

What percentage of individual adult females have weights between 75 kg and 83 kg?

This percentage is the pvalue of Z when $X = 83$ subtracted by the pvalue of Z when $X = 75$ . So:

X = 83

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{83 - 79}{22}$

$Z = 0.18$

$Z = 0.18$ has a pvalue of 0.5714.

X = 75

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{75- 79}{22}$

$Z = -0.18$

$Z = -0.18$ has a pvalue of 0.4286.

This means that 0.5714-0.4286 = 0.1428 = 14.28% of individual adult females have weights between 75 kg and 83 kg.

If samples of 100 adult females are randomly selected and the mean weight is computed for each sample, what percentage of the sample means are between 75 kg and 83 kg?

Now we use the Central Limit THeorem, when $n = 100$ . So $s = \frac{22}{\sqrt{100}} = 2.2.$