Find the sum of the first twentyterms of the arithmetic progression loga + loga² + loga^3

Mathematics

1 answer:

Elina [12.6K]3 years ago

3 0

Answer:

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Plz help asap Calculate: 3•7= A. -4 B. 4 C. 10 D. 21

Tju [1.3M]

The answer is D. 21 because your multiplying 3 and 7

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2 years ago

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Which equation is the inverse of 5 y + 4 = (x + 3) squared + one-half?

telo118 [61]

Answer:

The correct option is the last option d.) y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot

Step-by-step explanation:

the given equation is $5y + 4 =(x+3)^{2} + \frac{1}{2}$

Therefore we can write $5y\hspace{0.1cm} = (x+3)^{2} + \frac{1}{2} - 4 \hspace{0.3cm} \Rightarrow \hspace{0.2cm} 5y = (x+3)^{2} - \frac{7}{2} \hspace{0.3cm} \Rightarrow \hspace{0.3cm} y = \frac{(x+3)^{2}}{5} - \frac{7}{10}$

To find the inverse of the above function let us replace x with y and y with x.

Therefore we get

$x = \frac{(y+3)^{2}}{5} - \frac{7}{10}$

Now we write the above equation with only y on the Left hand side and we will obtain the inverse of the given function

$y = \pm \sqrt{5 (x + \frac{7}{10} )} \hspace{0.1cm} - \hspace{0.1cm} 3 \hspace{0.1cm} \Rightarrow\hspace{0.1cm} y = \pm \sqrt{5x + \frac{7}{2} } - \hspace{0.1cm} 3 \hspace{0.1cm}$

Therefore the correct option is the last option d.) y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot , $y = \pm \sqrt{5x + \frac{7}{2} } - \hspace{0.1cm} 3 \hspace{0.1cm}$

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2 years ago

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What is 34% written as a ratio? A) 34:1 B) 34:10 C) 34:100 D) 34:1000

VikaD [51]

34%/100=0.34 and that is equal to 34:100 aka 34/100.

Hoped I helped!

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2 years ago

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4. Can two lines be parallel and perpendicular? Explain.

lidiya [134]

Answer: No

Step-by-step explanation: First, we need to understand that parallel lines are coplanar lines that do not intersect. On the other hand, perpendicular lines are lines that intersect at a right angle.

However, lines can't be both parallel and perpendicular because they either intersect each other at a right angle or never intersect.

So no, two lines can't be both parallel and perpendicular.

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2 years ago

What is the tru solution to the logarithmic equation below? Log4[log4(2x)]=1

zaharov [31]

$\log_4(\log_42x)=1$