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weqwewe [10]
3 years ago
5

Simplify the expression where possible. (x 3y 2) 4

Mathematics
1 answer:
Ymorist [56]3 years ago
5 0

Answer:

4x 12y 8

Step-by-step explanation:

hopefully this helps you

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PLEASE ASAP FOR FULL POINTS
NARA [144]
It’s between B or C
Sorry if I’m wrong
3 0
3 years ago
From delta math:<br> Subtract -2x^2 + 3x - 9 from 8x^2 + 10x - 10
Leto [7]

Answer:

10x^2 + 7x - 1

Step-by-step explanation:

Step 1: Build the expression in numerical form.

  • (8x^2 +10x - 10) - (-2x^2 + 3x - 9)

Step 2: Distribute the negative sign.

  • 8x^2 +10x -10 + (-1)(-2x^2) + (-1)(3x) + (-1)(-9)
  • 8x^2 + 10x - 10 + 2x^2 + (-3x) + 9  

Step 3: Combine like terms.

  • (8x^2 +2x^2) + (10x -3x) + (-10+9)
  • 10x^2 +7x -1

Therefore, the answer is 10x^2 + 7x -1.

4 0
2 years ago
Almost there .......AAAAHHhH
madreJ [45]

Answer:

12/46

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What is the value of (16^3/2)^1/2
Alika [10]

<u><em>Answer: =1024. *The answer must be have positive sign.*</em></u>

Step-by-step explanation:

This question's it's about the order of operations. p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtract. It can also go left to right.

do exponents first.

16³/2=4098=2048¹/2

2048¹=2048

2048/2

divide left to right.

2048/2=1024

Hope this helps!

Thanks!

Have a great day!

4 0
3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
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