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True [87]
3 years ago
8

Maya's cat weighed 7 pounds 2 ounces last year. The cat gained 1 pound 8 ounces this year. What is the weight of maya's cat now

?
Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

8pounds And 10 ounces

Step-by-step explanation:

Add them to gether

gladu [14]3 years ago
6 0

Answer: 8 pounds  10 ounces

Step-by-step explanation:

7 ± 1 ⇒ 8

2 ± 8 ⇒ 10

⇒ 8 pounds  10 ounces

You might be interested in
1 of 3
Nonamiya [84]

Answer:

y = -1/2x + 3.5

Step-by-step explanation:

The gradients of perpendicular lines multiply to make -1. The gradient of the line given is 2, so 2 multiplied by something gives us -1. 2 × -1/2 = -1. The gradient of the perpendicular line is -1/2

y = -1/2x + c

Now we can substitute x = 1 and y = 3 into the equation:

  • 3 = -1/2(1) + c
  • 3 = -1/2 + c
  • c = 3 + 1/2
  • c = 3 1/2 or 3.5 or 7/2

The equation of the line is y = -1/2x + 3.5

Hope this helps!

3 0
3 years ago
NEED HELP ASAP. By what percent will a fraction change if its numerator is decreased by 30% and its denominator is decreased by
joja [24]

Answer:

0.7x/0.8y = x/y * 0.7/0.8 = x/y * 0.875

So the fraction is reduced by 12.5%

5 0
3 years ago
marco and suzi each mulyiplied 0.721 X 100 Marco got 7.21 for his product suiz got 72.1 for her product which student multiplied
Marianna [84]
Size got it right because it’s multiplied by 100
5 0
3 years ago
Find the coordinates of the missing endpoint if M is the midpoint of DF <br> F(2,9) M(-1,6)
Hunter-Best [27]

Answer:

(-4,3)

Step-by-step explanation:

6 0
3 years ago
Find the work required to move an object in the force field F = e^x + y (1, 1, z) along the straight line from A(0, 0, 0) to B(-
DENIUS [597]

\vec F(x,y,z)=(e^x+y)(1,1,z)

is conservative if we can find a scalar function f such that \nabla f=\vec F. This would require

f_x=e^x+y

f_y=e^x+y

f_z=(e^x+y)z

Integrating both sides of the first equation wrt x gives

f(x,y,z)=e^x+xy+g(y,z)

Differentiating both sides of this wrt y gives

f_y=x+g_y=1\implies g_y=1-x\implies g(y,z)=y-xy+h(z)

but we assumed g was a function of y and z, independent of x. So there is no such f and \vec F is not conservative.

To find the work, first parameterize the path (call it C) by

\vec r(t)=(1-t)(0,0,0)+t(-4,5,-5)=(-4t,5t,-5t)

for 0\le t\le1. Then

\vec r'(t)=(-4,5,-5)

and the work is given by the line integral,

W=\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^1(e^{-4t}+5t,e^{-4t}+5t,-(e^{-4t}+5t)5t)\cdot(-4,5,-5)\,\mathrm dt

W=\displaystyle\int_0^1(125t^2+5t+(25t+1)e^{-4t})\,\mathrm dt=\boxed{\frac{2207}{48}-\frac{129}{16e^4}}

8 0
3 years ago
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