Answer:

Step-by-step explanation:
Given
See attachment
Required
Determine the measure of 
.
So, we have:

Where:


Substitute these values in the above equation.


Collect Like Terms:


7/6
it’s positive because it’s going up
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To find the slope of the graph you pick any piece of the line, and divide the vertical difference between its ends by the horizontal difference between its ends. If the graph is distance versus time then the slope represents the speed.