Answer: Hello your question is incomplete below is the complete question
Let’s look at a different gene locus, we’ll call it B. The normal, wild type, the population was 100% BB. There are 150 Pakicetus in the population at present. Assume Charles had another mutation; this one at the B locus, to produce allele b. What is the gene frequency of allele b in the population if the population of Pakicetus reaches 100,000
answer : ≈ 1
Explanation:
<u>Determine the Gene frequency of allele b </u>
Population = 100,000
There are 150 Pakicetus in population i.e. 300 alleles at locus B
hence the frequency of b = 1/300 = 0.33%
Increase in population does not affect frequency of b ( HW equilibrium )
<em>therefore the Gene frequency of allele b </em>
= 0.33% * 0.33% * 100000 = 1.08
≈ 1
Answer:The rate of new cases of cancer (cancer incidence) is 442.4 per 100,000 men and women per year (based on 2013–2017 cases). The cancer death rate (cancer mortality) is 158.3 per 100,000 men and women per year (based on 2013–2017 deaths).Sep 25, 2020 ((not my writing for more go to cancer...gov)
Explanation: Have a brilliant day of learning! -Lily ^-^
22. D, that means the soil uhhhh helps the roots to grow??? Also because sunlight causes photosynthesis- sorry i’m not good at this hope it helps
A is the answer to this question
