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3 years ago

PLEASE HELP URGENT FOR GEOMETRY DO NOT WASTE ANSWERS WILL MARK BRAINLIEST

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

4 0

Answer:

reflect over y translate 6 down

Step-by-step explanation:

when we reflect over y it puts the figure right above the other one so we need to translate down

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Angle XYZ = 2X° and angle PQR = (8X -20)°. If angle XYZ and angle PQR are supplementary, find the measure of each angle. Angle P

Alchen [17]

Answer:

$PQR = 140$

Step-by-step explanation:

Given

$XYZ = 2X$

$PQR = 8X - 20$

Required

Find PQR

Since both angles are supplementary, we have:

$XYZ + PQR = 180$

This gives:

$2X + 8X - 20 = 180$

$10X - 20 = 180$

Collect Like Terms

$10X = 20 + 180$

$10X = 200$

Divide through by 10

$X = 20$

Substitute 20 for X in $PQR = 8X - 20$

$PQR = 8 * 20 -20$

$PQR = 140$

7 0

3 years ago

Hello - I have one last question that I think you might be able to help me with. Thanks~

Nata [24]

Let slant height be s
Height = 38yd. = h
Side = 42yd. = a

S² = h² + (a/2)²
= 38² + 21²
= 1444 + 441
= 1885
S = √1885
S = 43.42yd.

Lateral area = 1/2 × 4a × s
= 2 × 42 × 43.42
= 3646.99
= 3647 yd.²

7 0

3 years ago

Read 2 more answers

Factor completely x3 + 4x2 + 8x + 32. (x + 4)(x2 + 8) (x − 4)(x2 − 8) (x − 4)(x2 + 8) (x + 4)(x2 − 8)

icang [17]

$\tt x^3+4x^2+8x+32\\\\=x^2(x+4)+8(x+4)\\\\=\boxed{\tt(x+4)(x^2+8)}$

7 0

3 years ago

Read 2 more answers

While Al was staying overnight on vacation with his friends his only expenses were for food. Al spent $7.52 on lunch, $9.74 on d

Serggg [28]

Answer:

$25.10

Step-by-step explanation:

lunch=$7.52

dinner=$9.74

breakfast=$5.16

money left=$2.68

make total money he began with ‘x’

to find the total money he began with it will be

x-lunch+dinner+breakfast=money left

x-$7.52+$9.74+$5.16=$2.68

x-$22.42=$2.68

x=$2.68+$22.42

x=$25.10

8 0

2 years ago

Which of the following sets of lengths could not be the side lengths of a triangle?

docker41 [41]

To find out if the three side lengths can create a triangle, the three smaller lengths must be greater than the longer length.

$\bf~Option~A$

$\sf~3~meters,5~meters,7~meters$

$\sf3+5=8>7$

So this can create a triangle.

$\bf~Option~B$

$\sf1~yard,1.25~yards,1.5~yards$

$\sf1+1.25=2.25>1.5$

So this can create a triangle.

$\bf~Option~C$

$\sf5~inches,10.5~inches,17~inches$

$\boxed{\sf5+10.5=15.5$

So this cannot create a triangle.

$\bf~Option~D$

$\sf15~millimeters,18~millimeters,30~millimeters$

$\sf15+18=33>30$

So this can create a triangle.

Therefore, your answer is Option C.

8 0

3 years ago