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Ber [7]
4 years ago
13

Please help me now!!!

Mathematics
2 answers:
Viktor [21]4 years ago
6 0
Any equilateral triangle has 3 angles of 60° each as all the angles have to add to 360° and there must be 3 equal sides. As no side length is specified you can make infinitely many different equilateral triangles provided they all have different side lengths.
Korvikt [17]4 years ago
3 0

Answer:

<h2>D. Infinitely many</h2>

Step-by-step explanation:

In this case, the number of equilateral triangles we could make is restricted by the length of its sides. However, this problem doesn't restrict any side, it doesn't specifies a length for all sides, it only gives the angles, which have to be equal to 60° because it's a equilateral triangle.

This means that we could make infinitely many triangles with angles of 60°, it could be a triangles with sides of 1 unit long, 2 units, or 100 units long, all of them would have angles of 60°.

Therefore, the right answer is D.

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Steve can run 1 2/9 miles in 10 minutes. How many miles can he run in 30 minutes?
mariarad [96]

Answer:

3 2/3

Step-by-step explanation:

remember to give me brainliest cause I helped you

 

4 0
3 years ago
Multiply this expression and check:(4y^3+4y^2+8)(6y-4)
emmasim [6.3K]
(4y³ + 4y²+8)(6y - 4)

Simplify.

24y⁴ - 16y³ + 24y³ - 16y² + 48y - 32

Add like terms.

24y⁴ + (-16y³ + 24y³) -16y² + 48 - 32

Simplify.

24y⁴ + 8y³ - 16y³ + 16

~Hope I helped!~
7 0
4 years ago
How are percent transmittance and absorbance related algebraically?
statuscvo [17]

Answer:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Absorbance is the inverse of transmittance so,

A = 1/T

Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:  


A ∝ b · c

As Transmittance, T =\dfrac{P}{P_0}

% Transmittance, \%T=100\times T

Absorbance,

A=\log_{10} \dfrac{P_0}{P}\\\\A =\log_{10}\times \dfrac{1}{T}\\\\A=\dfrac{\log_{10} 100}{\%T}\\\\A=(2 - log_{10})\times \%T

Hence, A=\log_{10}\times \dfrac{1}{T} is the algebraic relation between absorbance and transmittance.


8 0
3 years ago
Find the first 5 terms in the following sequence: a1 = 23, a, an-1 + 7, n &gt; 2​
sasho [114]

Answer:

Step-by-step explanation:

ok ok ok ok ok ok

6 0
3 years ago
Suppose that a household's monthly water bill (in dollars) is a linear function of the amount of water the household uses (in hu
olga nikolaevna [1]

Answer:

I hope that you are doing well, during this weird time; and that this message finds you in a good place.

To get you started on this problem, you will want to think about how to go about graphing this linear function. You want to keep in mind that you want to plot your dependent variable on the y-axis, as it changes with respect to your independent variable (plotted on the x-axis). In this problem, the cost of the water bill depends on the amount of water used, in HCF. So the graph should be plotted with cost on the y-axis, and HCF on the x-axis.

It follows that you are given the coordinates of (16, $48.37) and (22, y2); where y2 represents the cost when using 22 HCF. You are also given the slope of your line (m, in y = mx + b format). You may recall that you can set-up a slope as the change in y over the change in x, or the "rise over the run" [m = (y2-y1) / (x2-x1)]. We can set this problem up, using this equation to solve for y2 (the cost at 22 HCF) algebraically.

So we would set up the problem as 1.65 = (y2-48.37)/(22-16). We then solve by combining like-terms and using inverse operations as follows:  

  1.65 = (y2 - 48.37) / 6

  1.65(6) = y2 - 48.37

  9.9 = y2 - 48.37

  y2 = $58.27

Step-by-step explanation:

3 0
2 years ago
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