6 165.1 159.2 163.5 174.8 173.2 177.6 174.3 164.1 171.4 find the median

Mathematics

1 answer:

Katen [24]3 years ago

5 0

159.2, 163.5, 164.1, 171.4, 173.2, 174.3, 174.8, 177.6, 6165.1

mean= 835.9
median= 173.2
mode= N/A

You might be interested in

The graph of y=f(x) is above. If f(−4)=k, what is the value of f(k)?

cupoosta [38]

Answer:

The answer is B, which is -1.5.

3 0

2 years ago

Emilio compra 3,6 kg de manzanas a 1,45 euros el kilo ¿Cuánto pagara por las manzanas?

Ad libitum [116K]

Answer:

Emilio compra kg De manzanas a euros el kilo cuanto pagara por Las manzanas

3 0

2 years ago

Tanya finds 22 leaves Maurice finds 5 more leaves than Tanya finds how many leaves do the two children find

Mila [183]

Answer:

22 + 27 = 49

:) :)

8 0

2 years ago

Read 2 more answers

Pls help me I give pick BRAINLIEST!!

mariarad [96]

Answer:

Step-by-step explanation:

56/7=8

8x3=24

6 0

2 years ago

A sphere of radius r is cut by a plane h units above the equator, where

Anika [276]

Consider the top half of a sphere centered at the origin with radius $r$ , which can be described by the equation

$z=\sqrt{r^2-x^2-y^2}$

and consider a plane

$z=h$

with $0$ . Call the region between the two surfaces $R$ . The volume of $R$ is given by the triple integral

$\displaystyle\iiint_R\mathrm dV=\int_{-\sqrt{r^2-h^2}}^{\sqrt{r^2-h^2}}\int_{-\sqrt{r^2-h^2-x^2}}^{\sqrt{r^2-h^2-x^2}}\int_h^{\sqrt{r^2-x^2-y^2}}\mathrm dz\,\mathrm dy\,\mathrm dx$

Converting to polar coordinates will help make this computation easier. Set

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\var\phi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi$

Now, the volume can be computed with the integral

$\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_0^{\arctan\frac{\sqrt{r^2-h^2}}h}\int_{h\sec\varphi}^r\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

You should get

$\dfrac{2\pi}3\left(r^3\arctan\dfrac{\sqrt{r^2-h^2}}h-\dfrac{h^3}2\left(\dfrac{r\sqrt{r^2-h^2}}{h^2}+\ln\dfrac{r+\sqrt{r^2-h^2}}h\right)\right)$

5 0

3 years ago