All categories

3 years ago

Write a two-column proof

Mathematics

1 answer:

miskamm [114]3 years ago

6 0

I hope this helps you

You might be interested in

What is the vertex of each function

cricket20 [7]

Answer:

Step-by-step explanation:

note :

f(x) =a(x-h)²+k

the vertex is : (h,k)

continu .........

7 0

3 years ago

The sets of numbers 7, 24, 25 and 9, 40, 41 are Pythagorean triples. Use what you know about the Pythagorean Theorem and explain

Ipatiy [6.2K]

Answer:

See below

Step-by-step explanation:

Because $a^2+b^2=c^2$ has to remain true, then $7^2+24^2=25^2$ is a Pythagorean Triple as $49+576=625$ . Also, $9^2+40^2=41^2$ works because $81+1600=1681$ .

3 0

3 years ago

Write the rule for the nth term of the following sequence.

denis-greek [22]

Answer:

$2^{n-3}$ is the nth term of the given sequence.

Step-by-step explanation:

The sequence given is

$\frac{1}{4},\frac{1}{2},1,2,4 .....$

We can clearly see that 1st term is $\frac{1}{4}$ and 2nd term is $\frac{1}{2}$

2nd term is obtained by multiplying the 1st term by 2.

2nd term is $\frac{1}{2}$ and 3rd term is 1.

3rd term is obtained by multiplying the 2nd term by 2.

3rd term is 1 and 4th term is 2.

4th term is obtained by multiplying the 3rd term by 2.

Clearly, the given series is a Geometric Progression(GP) with

First term, $a = \frac{1}{4}$

Common Ratio, $r = 2$

We know that $n^{th}$ term for a GP is:

$a_n = ar^{n-1}$

Putting values of a and r

$a_n = \dfrac{1}{4}2^{n-1}\\a_n = \dfrac{1}{2^{2} }2^{n-1}\\a_n = 2^{n-1-2}\\a_n = 2^{n-3}$

Hence, $2^{n-3}$ is the nth term of the given sequence.

3 0

3 years ago

I will give brainlest, please help me!

Gemiola [76]

Answer:

1,3,6,10,15,21,27

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Do you guys know this

anygoal [31]

Answer: the answer is c

Step-by-step explanation:

3 0

3 years ago