Answer:
c
Step-by-step explanation:
Answer:
Yes, we can assume that the percent of female athletes graduating from the University of Colorado is less than 67%.
Step-by-step explanation:
We need to find p-value first:
z statistic = (p⁻ - p0) / √[p0 x (1 - p0) / n]
p⁻ = X / n = 21 / 38 = 0.5526316
the alternate hypothesis states that p-value must be under the normal curve, i.e. the percent of female athletes graduating remains at 67%
H1: p < 0.67
z = (0.5526316 - 0.67) / √[0.67 x (1 - 0.67) / 38] = -0.1173684 / 0.076278575
z = -1.538681
using a p-value calculator for z = -1.538681, confidence level of 5%
p-value = .062024, not significant
Since p-value is not significant, we must reject the alternate hypothesis and retain the null hypothesis.
The variable in this equation is b, therefore we have to calculate the value of b.
-38=2b+25-(-7b)
-38=2b+25+7b
2b+7b=-38-25
9b=-63
b=-63/9
b=-7
Answer: the value of the variable is b=-7
We can check it out this answer:
-38=2b+25-(-7b)
-38=2(-7)+25-(-7(-7))
-38=-14+25-49
-38=-38
A- the length of the side of a square
P = 16
P = 4a → 4a = 16 |:4 → a = 4
The diagonal of the square: d = a√2
therefore d = 4√2
