Would it be possible to conduct an UV/Vis spectroscopy experiment on a sample of the compound C3H3O2? Explain.

Chemistry

2 answers:

never [62]4 years ago

7 0

Different substances can interact differently with light. So for me, I think the answer would be yes. It is possible <span>to conduct an UV/Vis spectroscopy experiment on a sample of the compound C3H3O2. Every substance is unique and has its own light interactions.</span>

zalisa [80]4 years ago

3 0

Answer: Yes, we can conduct a UV/Vis spectroscopy experiment for $C_3H_3O_2$ compound.

Explanation: UV/Vis Spectroscopy is used for the quantitative determination of conjugated organic compounds, biological macromolecules and transition metal ions.

We are given a compound $C_3H_3O_2$ , in which conjugation is present and undergoes $\pi-\pi^*$ transition. This transition means that the energy gap is low and hence the wavelength will be more.

According to the Planck's relation:

$E=\frac{hc}{\lambda}$

Energy and wavelength follow inverse relation.

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2FeCl3 + MgO -> Fe2O3 + 3MgCl2<br> Convert 3.00 moles of MgO to moles of Fe2O3

nikitadnepr [17]

71.8 g of iron (III) oxide (Fe₂O₃) were produced from 3 moles of magnesium oxide (MgO).

Explanation:

We have the following chemical reaction:

2 FeCl₃ + 3 MgO → Fe₂O₃ + 3 MgCl₂

We see from the chemical reaction that 3 moles of magnesium oxide (MgO) will produce 1 mole of iron (III) oxide (Fe₂O₃).

number of moles = mass / molar weight

mass = number of moles × molar weight

mass of Fe₂O₃ = 1 × 71.8 = 71.8 g

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3 years ago

A 0.539 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M(s)+H2SO4(aq)⟶MSO4(aq)+H2(g) A v

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Answer:

The molar mass of the metal is 54.9 g/mol.

Explanation:

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PH₂ = Patm - Pwater = 1.0079 bar - 0.03167 bar = 0.9762 bar

The pressure of H₂ is:

$0.9762bar.\frac{1atm}{1.013bar} =0.9637atm$