The only coefficient is a 2 behind the reactant hydrochloride.
Answer:
increase
Explanation:
Reactions that are initiated by light are called photochemical reactions. The brighter the light, the faster the reaction.
From Faraday's 1st law of electrolysis,
Total electricity passed into system = Q = IT = 250 X 24 X 60 X 60
= 2.16 X 10^7 C
We know that, 96500 C = 1 F
∴ 2.16 X 10^7 C = <span>223.8 F
</span>
Now, number of moles of<span> MnO2 deposited = 223.8/2=111.9
</span>
Finally, 1 mole of MnO2 ≡ 86.94 g
∴ 111.9 mole of MnO2 ≡ 111.9 X 86.94 = 9728 g
Thus, <span>mass of MnO2 that will be deposited at anode = 9728 g</span>
Answer:
6.05 g
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
From the question ,
M = 200mM
Since,
1 mM = 10⁻³ M
M = 200 * 10⁻³ M
V = 250 mL
Since,
1 mL = 10⁻³ L
V = 250 * 10⁻³ L
The moles can be calculated , by using the above relation,
M = n / V
Putting the respective values ,
200 * 10⁻³ M = n / 250 * 10⁻³ L
n = 0.05 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
m = 121 g/mol
n = 0.05 mol ( calculated above )
The mass of tri base can be calculated by using the above equation ,
n = w / m
Putting the respective values ,
0.05 mol = w / 121 g/mol
w = 0.05 mol * 121 g/mol
w = 6.05 g
