<u>Answer:</u> The volume of stock solution needed is 0.016 L
<u>Explanation:</u>
To calculate the volume of stock solution, we use the equation:
where,
are the molarity and volume of the stock solution
are the molarity and volume of diluted solution
We are given:
Putting values in above equation, we get:
Hence, the volume of stock solution needed is 0.016 L
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The answer is in the picture which is given below:
No, the dilution does not change the number of moles dissolved
Explanation:
We can see that,
The molarity of the solution was 0.50 M
The volume of the solution is 10 ml.
No of moles of the solute was= volume * concentration
= 10 X 10^-3* 0.50
= 5*10^-3 moles
When the solution is diluted from 10 ml to 100ml, the molarity or concentration changes but number of moles remains constant.
The molarity of 100 ml solution will be
c=n/V
= 5*10^-3*/100*10^-3
= 0.05
when the solution is diluted to 100ml from 10 ml molarity changes from 0.5M TO 0.05 M
