The oxidation number of I (iodine) decreases the in the described chemical reaction from 0 to -1.
Explanation:
We have the following chemical reaction:
I₂ + 2 KCl → KI + Cl₂
The following atoms have a change in the oxidation number:
I with a 0 oxidation number (in I₂) goes to I with -1 oxidation number (in KI) by receiving 1 electron.
Cl with a -1 oxidation number (in KCl) goes to I with 0 oxidation number (in Cl₂) by losing 1 electron.
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oxidation number
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Answer: electrons are arranged in shells around an atom's nucleus.
Explanation:
As a result of high winds and water from a storm surge, homes, businesses, and crops may be destroyed or damaged, public infrastructure may also be compromised, and people may suffer injuries or loss of life.
Based on the chemical equation, to balance the equation we use 2 as a coefficients of HCl on left hand side of reaction.
<h3>What is balanced equation?</h3>
Balanced chemical equations are those equation in which each entities are present in same amount on left side as well as on the right side of the chemical reaction.
Given chemical reaction is:
Zn + HCl → ZnCl₂ + H₂
Above reaction is not balanced equation as number of chlorine and hydrogen atoms are not same, so balanced equation will be:
Zn + 2HCl → ZnCl₂ + H₂
Hence we add 2 as a coefficient of HCl to balance the equation.
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Answer:
The answer to your question is 52.35 g of O₂
Explanation:
mass of oxygen = ?
mass of KClO₃ = 66.8 g
Chemical balanced reaction
KClO₃ ⇒ 2 KCl + 3O₂
Process
1.- Calculate the molar mass of KClO₃ and Oxygen
KClO₃ = 39 + 35.5 + (16 x 3) = 122.5 g
O₂ = 16 x 6 = 96 g
2.- Write proportions to solve this problem
122.5 g of KClO₃ ----------------- 96 g of O₂
66.8 g ----------------- x
x = (66.8 x 96) / 122.5
x = 6412.8/122.5
x = 52.35 g of O₂