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Ymorist [56]
3 years ago
14

What is the value of 16 times 4

Mathematics
2 answers:
SOVA2 [1]3 years ago
5 0

16 x 4 = 64

( 6 x 4 = 24, 10x 4 = 40, 24 + 40 = 64)

Elanso [62]3 years ago
3 0

16 times 4 equals to 64. 64 is simply 4 sets of 16 added together.

Other factors of 64 include, 1,2,4,8,16,32, and 64.

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GenaCL600 [577]

Given:

Consider the given function:

f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot(x-b)}{a-b}

To prove:

f(a)+f(b)=f(a+b)

Solution:

We have,

f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot (x-b)}{a-b}

Substituting x=a, we get

f(a)=\dfrac{b\cdot(a-a)}{b-a}+\dfrac{a\cdot (a-b)}{a-b}

f(a)=\dfrac{b\cdot 0}{b-a}+\dfrac{a}{1}

f(a)=0+a

f(a)=a

Substituting x=b, we get

f(b)=\dfrac{b\cdot(b-a)}{b-a}+\dfrac{a\cdot (b-b)}{a-b}

f(b)=\dfrac{b}{1}+\dfrac{a\cdot 0}{a-b}

f(b)=b+0

f(b)=b

Substituting x=a+b, we get

f(a+b)=\dfrac{b\cdot(a+b-a)}{b-a}+\dfrac{a\cdot (a+b-b)}{a-b}

f(a+b)=\dfrac{b\cdot (b)}{b-a}+\dfrac{a\cdot (a)}{-(b-a)}

f(a+b)=\dfrac{b^2}{b-a}-\dfrac{a^2}{b-a}

f(a+b)=\dfrac{b^2-a^2}{b-a}

Using the algebraic formula, we get

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f(a+b)=b+a

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Now,

LHS=f(a)+f(b)

LHS=a+b

LHS=f(a+b)

LHS=RHS

Hence proved.

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Answer:

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Answer:

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