Insert x = 7
so 3/(7+2) - sqr (7-3)
=3 / (9) - sqr (4)
= 1/3 - 2
=1/3 - 6/3
= -5/3
We want double sixes. This means that we want both the first roll and the second roll to be 6.
The given point is given as (r1 , r2) where:
r1 is output from first roll
r2 is output from second roll
Since we want both outputs to be 6, therefore, the answer would be: (6,6)
Answer:
Binomial theorem, statement that for any positive integer n, the nth power of the sum of two numbers a and b may be expressed as the sum of n + 1 terms of the form.
