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LekaFEV [45]
3 years ago
15

Simplify 4 radical 20- 3 radical 45

Mathematics
1 answer:
liberstina [14]3 years ago
8 0
4\sqrt{20}-3\sqrt{45}= 4*2\sqrt{5}-3*3\sqrt{5}= \\\\ =8\sqrt{5}-9\sqrt{5}= \\\\ =\boxed{-\sqrt{5}}
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How many solutions are there in the given equation?<br> y = 2x² + 6x + 4
tigry1 [53]

Step-by-step explanation:

Use the quadratic formula

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Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

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brainliest and follow and thanks

8 0
3 years ago
Help for geometry asap
Llana [10]

<u>Given</u>:

Four lines are marked proportion, the length of TW can be determined by

TW=a+4+b

<u>Value of a:</u>

Let us set the proportion for the given lines.

Thus, we have;

 \frac{a}{7}=\frac{4}{5}

5a=28

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Thus, the value of a is 5.6

<u>Value of b:</u>

Let us set the proportion for the given lines.

Thus, we have;

 \frac{4}{5}=\frac{b}{5}

20=5b

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Thus, the value of b is 5.

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TW=5.6+4+4

TW=13.6

Thus, the length of TW is 13.6

3 0
3 years ago
Which measure represents the standard deviation of the sample means and is used in place of the population standard deviation wh
Ksivusya [100]

The measure represents the standard deviation of the sample means and is used in place of the population standard deviation when the population parameters are unknown is; t-test.

<h3>Which measure is used when the population parameters are unknown?</h3>

A hypothesis test for a population mean when In the case that the population standard deviation, σ, is unknown, carrying out a hypothesis test for the population mean is done in similarly like the population standard deviation is known. A major distinctive property is that unlike the standard normal distribution, the t-test is invoked.

Read more on t-test;

brainly.com/question/6501190

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4 0
2 years ago
The circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm. (a) Use differentials to estimate the ma
andreev551 [17]

The maximum error in the calculated surface area is 24.19cm² and the relative error is 0.0132.

Given that the circumference of a sphere is 76cm and error is 0.5cm.

The formula of the surface area of a sphere is A=4πr².

Differentiate both sides with respect to r and get

dA÷dr=2×4πr

dA÷dr=8πr

dA=8πr×dr

The circumference of a sphere is C=2πr.

From above the find the value of r is

r=C÷(2π)

By using the error in circumference relation to error in radius by:

Differentiate both sides with respect to r as

dr÷dr=dC÷(2πdr)

1=dC÷(2πdr)

dr=dC÷(2π)

The maximum error in surface area is simplified as:

Substitute the value of dr in dA as

dA=8πr×(dC÷(2π))

Cancel π from both numerator and denominator and simplify it

dA=4rdC

Substitute the value of r=C÷(2π) in above and get

dA=4dC×(C÷2π)

dA=(2CdC)÷π

Here, C=76cm and dC=0.5cm.

Substitute this in above as

dA=(2×76×0.5)÷π

dA=76÷π

dA=24.19cm².

Find relative error as the relative error is between the value of the Area and the maximum error, therefore:

\begin{aligned}\frac{dA}{A}&=\frac{8\pi rdr}{4\pi r^2}\\ \frac{dA}{A}&=\frac{2dr}{r}\end

As above its found that r=C÷(2π) and r=dC÷(2π).

Substitute this in the above

\begin{aligned}\frac{dA}{A}&=\frac{\frac{2dC}{2\pi}}{\frac{C}{2\pi}}\\ &=\frac{2dC}{C}\\ &=\frac{2\times 0.5}{76}\\ &=0.0132\end

Hence, the maximum error in the calculated surface area with the circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm is 24.19cm² and the relative error is 0.0132.

Learn about relative error from here brainly.com/question/13106593

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3 0
2 years ago
What is 60% of 14.50
Ilia_Sergeevich [38]
60% of 14.50 = 8.7
<span><span><span><span><span><span>
Hope I Helped!!</span></span></span></span></span></span>
6 0
3 years ago
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