Find the value of x. If necessary, you may learn what the markings on a figure indicate. 74°

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

6 0

X=61°

please see the attached picture for full solution..

Hope it helps...

Good luck on your assignment...

marissa [1.9K]3 years ago

5 0

Answer:

x = 61

Step-by-step explanation:

Left hand triangle containing 1 angle of 74

Label the other angle opposite the marked side also as 74

Find the third angle. Call it y.

y + 74 + 74 = 180 Combine like terms

y + 148 = 180 Subtract 148 from both sides.

y = 180 - 148

y = 32

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Now work with the triangle on the right.

label the angle making up the right angle = z

32 + z = 90 These two angles are complementary = 90

32 - 32 + z = 90 - 32 Subtract 32 from both sides

z = 58 Use 58 wherever you see z

x + x + z = 180 Substitute

2x + 58 = 180 Subtract 58 from both sides

2x = 122 Divide by 2

x = 61

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Please help find domain and range

Oxana [17]

<h3>Answer: Choice A</h3>

Domain: x > 4
Range: y > 0

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Explanation:

We want to avoid having a negative number under the square root. Solving $x-4 \ge 0$ leads to $x \ge 4$

So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.

So in reality, the domain is x > 4.

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The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.

We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression $\frac{3}{\sqrt{x-4}}$ is positive because positive/positive = positive.

Therefore, the range of the given equation is y > 0

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The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).