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2 years ago

Classify each number below as a rational number or an irrational number. rational irrational

Mathematics

2 answers:

Vadim26 [7]2 years ago

6 0

Rational
Irrational
Rational
Rational
Irrational

puteri [66]2 years ago

4 0

-√25 rational

$\frac{14}{19}$ irrational

9π irrational

2√2 irrational

87.39... rational

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The graph of an exponential function passes through the point (0,15) and (1,10). What is the equation of the exponential functio

Vilka [71]

Answer:

$y=15(\frac{2}{3})^x$

Step-by-step explanation:

we know that

The equation of a exponential function is of the form

$y=a(b^x)$

where

a is the initial value or y-intercept

b is the base of the exponential function

In this problem we have

$a=15$ ----> the y-intercept is given

substitute

$y=15(b^x)$

we have the other ordered pair (1,10)

substitute the value of x and the value of y and solve for b

$10=15(b^1)\\10=15b$

$b=\frac{10}{15}=\frac{2}{3}$

substitute

$y=15(\frac{2}{3})^x$

see the attached figure to better understand the problem

7 0

2 years ago

Which is greater 3.75 3.750

guapka [62]

Answer:

None

Step-by-step explanation:

They are the same number

5 0

2 years ago

Can someone help me with this problem please

Makovka662 [10]

Answer:

Circumference=2πr or πd

So:

3.14 × 6cm

=18.84cm

6 0

2 years ago

Which of the following statements represents the distributive property?

Lana71 [14]

Answer:

The answer to your question is B.

3 0

3 years ago

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0

1 year ago