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3 years ago

Question 16 please about the line segment

Mathematics

1 answer:

gavmur [86]3 years ago

8 0

Find the number of boxes in segment PR and then square it, so 13 squared + the same thing on the other leg, so 5 squared

169+25= 194

squareroot of 194
gives u 13.928...

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What is the measure of EA? Need help ASAP!

Ghella [55]

The measurement is 51

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3 years ago

the value of a baseball card can be represented by the equation y equals 3x + 39 where X represents the number of years that Rob

Blababa [14]

Answer:

I need the values of either X or Y to solve this. I can solve for what X is though.

Step-by-step explanation:

A: X = -12

B: X =78

C: X = 12.13

I hope this helps you, but since both X and Y are unknown variables, you can't solve it, only simplify (which it already is.)

3 0

3 years ago

How do you count by 8s and 7s

galben [10]

Answer:

just add 8+8+8 until you get to the number u want/need and the same with 7. Or you can multiply.

8x1=8

7x1=7

8x3=24 (8+8+8=24)

7x3=21 (7+7+7=21)

etc.

Hope it helps!

7 0

3 years ago

Need math help. Thanks in advance.

Mademuasel [1]

9. D because it fits the description when it is graphed.
11. D because it has the correct vertex, which is (1.5, 4.75).
12. f(x)=-4(x-2)²+16 works with the table and provided graph!
13. 0 isn't a zero for f(x), so B is correct (the zeros are 1/2 and 4).
14. The width is about 3.831.
15. The answer is B because the equation for a parabola in this form is:
f(x) = (x - r₁)(x - r₂)

Every one of these except for 15 was solved using desmos, a graphing calculator.

Hope this helps!

7 0

2 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

3 years ago