The third one down is the correct answer. (-55 and 1)
58, 62, 71, 73, 84, 89, 91, 91, 93, 97, 98, 101,104
Five number summary:
1) minimum = 58
2) 1st quartile = 72
3) median = 91
4) 3rd quartile = 98
5) maximum = 104
__________
--------<u>| | </u>|------------
58 72 91 98 104
Here, we want to find the diagonal of the given solid
To do this, we need the appropriate triangle
Firstly, we need the diagonal of the base
To get this, we use Pythagoras' theorem for the base
The other measures are 6 mm and 8 mm
According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides
Let us have the diagonal as l
Mathematically;
![\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20l%5E2%3D6%5E2%2B8%5E2%20%5C%5C%20l%5E2%5Ctext%7B%20%3D%2036%20%2B%2064%7D%20%5C%5C%20l%5E2%5Ctext%7B%20%3D100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%2010%20mm%7D%20%5Cend%7Bgathered%7D)
Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above
Thus, we calculate this using the Pytthagoras' theorem as follows;
![\begin{gathered} d^2=5^2+10^2 \\ d^2\text{ = 25 + 100} \\ d^2\text{ = 125} \\ d\text{ = }\sqrt[]{125} \\ d\text{ = }11.2\text{ mm} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d%5E2%3D5%5E2%2B10%5E2%20%5C%5C%20d%5E2%5Ctext%7B%20%3D%2025%20%2B%20100%7D%20%5C%5C%20d%5E2%5Ctext%7B%20%3D%20125%7D%20%5C%5C%20d%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B125%7D%20%5C%5C%20d%5Ctext%7B%20%3D%20%7D11.2%5Ctext%7B%20mm%7D%20%5Cend%7Bgathered%7D)
The value of "b" is the y-intercept.
In order to figure out slope-intercept form you need 1 coordinate and the slope.
1) Find the slope, using the 2-point slope formula: "m= y2-y1 / x2-x1".
ex. m= -5 - 3 / -4 - -6 (simplify)---> m= -4
2) Fill in the blanks for point-slope formula: "y - y1 = m (x - x1)"
(choose one coordinate, it doesn't matter which one)
ex. y - -5 = -4 (x - -4)
3) Then use basic algebra to simplify.
Length X width = area. for this problem, just divide the area of 756 sq. inches by the length of 108 in. to find the width.
