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marin [14]
3 years ago
13

Solution -9-8(1+4h)= -17

Mathematics
2 answers:
geniusboy [140]3 years ago
5 0
Step 1. <span>Add </span>9<span> to both sides

</span>-8(1+4h)=-17+9

Step 2. Simplify -17+9 to -8

-8(1+4h)=-8

Step 3. Divide both sides by -8

1+4h=1

Step 4. Cancel 1 on both sides

4h=0
 Step 5. Divide both sides by 4

h=0

Done! :) Hope this helps! :)

To check -9-8(1+4h)=-17 follow these steps below:

Step 1. Let h = 0

-9-8*(1+4*0)=-17

Step 2. Simplify 4 * 0 to 0

-9-8*(1+0)=-17

Step 3. Simplify 1 + 0 to 1

-9-8*1=-17
<span>
Step 4. </span><span>Simplify  8 * 1 to 8
</span>
-9-8=-17
<span>
Step 5. </span><span>Simplify -9 -8 to -17
</span><span>
</span>-17=-17
<span>
Done! :)
 </span>
podryga [215]3 years ago
4 0
-9 -8 (1+4h) = -17

-9 -8 - 32h = -17

-17 -32h = -17

-32h = 0

h = 0 
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3 years ago
Can someone help me with this question?????????
pishuonlain [190]
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4 0
3 years ago
Cards. A deck of 52 cards is shuffled and dealt. Find the probabilities of the following events: a) the tenth card is a queen; b
Veronika [31]

Answer:

  • 0.0374
  • 0.0010

Step-by-step explanation:

number of cards = 52

number of queen = 4

number of spades = 13

A) probability that the tenth card is a queen

drawn time (r) = 1

position of success(x) = 10th

p = 4/52

P( x,r,p) = x-1Cr-1*p^(r) * q^(x-r)

p(10,1,4/52) = 9C0(4/52)^1 * (48/52)^9 = 0.0374

B) probability the twentieth card is a spade

x = 20

r = 1

p = 13 / 52

P(20,1,26/52) = 19C0(26/52)^1 * (26/52)^19 = 0.0010

c)  The last five cards been spades

p(last five cards been spades )

p(48..52, 5, 13/52 ) = 47...52C4(13/52)^5 * (39/52)^48..52 - 5

 

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