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2 years ago

Nine times a number decreased by four

Mathematics

2 answers:

Wewaii [24]2 years ago

7 0

The answer for this question is 9x-4

PolarNik [594]2 years ago

5 0

Answer: 9x - 4

Step-by-step explanation:

We know that a number must be decreased by four. Let's break it up a little.

Nine times some number. We don't know what nine will be multiplied by, so we will just write a placeholder number: x. This number will be multiplied by nine. So it will turn into 9x.

We must decrease (subtract) from this by four. Subtracting 9x by four can be written as 9x - 4.

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Answer:

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Step-by-step explanation:

A conversion factor is written based on the equality between the two units

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Find the first term and the common ratio third term =6 and seventh term= 96

mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

We are given: third term = 6 i,e

$a_3=a_1r(3-1)\\6=a_1r^2----eq(1)$

Seventh term = 96

$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$

So, Common Ratio r = 2

Finding First term using eq(1)

$a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}$

So, First term a₁ = 3/2 and common ratio r = 2

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2 years ago

A regular triangular pyramid has a base and lateral faces that are congruent equilateral triangles. It has a lateral surface are

TEA [102]

We know that

[lateral surface area of a regular triangular pyramid]=3*[area of one equilateral triangle]
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[surface area of the regular triangular pyramid]=lateral area+area of the base

area of the base is equals to the area of the lateral sides because are equilateral triangles

therefore
area of the base=27 ft²

[surface area of the regular triangular pyramid]=81+27----> 108 ft²

the answer is
the surface area of the regular triangular pyramid is 108 ft²

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Answer:

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