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4 years ago

Solve each system by elimination

Mathematics

1 answer:

Lera25 [3.4K]4 years ago

4 0

First equation 2(4X -5y = 4)
8X -10y = 8

Elimination 8x -10y =8
-8x + 9y =-8

-y =0
-1(-y =0)
y =0

8x -10(0) =8
8x =8
(8x =8)/8
x = 1

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-4x+-6y=24 how do you solve?

alina1380 [7]

So,

Let's manipulate this into the y=mx + b form.

Add 4x to both sides
-6y = 4x + 24

Divide both sides by -6
$y = \frac{4}{-6} x - 4$

Just use the slope to find the points you need.

The y-intercept is (0,-4).

The slope is $\frac{4}{-6}$ . Finding the next point:
(-6,0)

You could have also used the slope intercept method.

-4(0) - 6y = 24
-6y = 24

Divide both sides by -6
y = -4
(0,-4)

-4x - 6(0) = 24
-4x = 24

Divide both sides by -4
x = -6
(-6,0)

3 0

3 years ago

Read 2 more answers

How do you get this to its Standard Form? And is it linear?

Alchen [17]

let's bear in mind that

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

so, let's do away with the denominators by multiplying both sides by the LCD of all fractions, in this case 6.

$\bf \cfrac{x}{2}=\cfrac{y+3}{6}\implies\stackrel{\textit{multiplying by }\stackrel{LCD}{6}}{6\left( \cfrac{x}{2} \right)=6\left( \cfrac{y+3}{6} \right)}\implies 3x=y+3\implies \stackrel{\textit{standard form}}{3x-y=3}$

4 0

4 years ago

Read 2 more answers

Find the following: sin A cos A tan A cot A sec A csc A

DedPeter [7]

Step-by-step explanation:

we use the law of sine :

sin(A)/a = sin(B)/b = sin(C)/c

with the related angles being opposite of the lines.

so, we have

sin(A)/1 = sin(A) = sin(90)/ sqrt(10) = 1/ sqrt(10) =

= 0.316227766...

cos²(A) + sin²(A) = 1

cos(A) = sqrt(1 - sin²(A)) = sqrt(1 - 0.1)) = sqrt(0.9) =

= 0.948683298...

tan(A) = sin(A)/cos(A) = 0.333333333...

cot(A) = 1/tan(A) = 3

sec(A) = 1/cos(A) = 1.054092553...

csc(A) = 1/sin(A) = 3.16227766...

7 0

3 years ago

Which property is illustrated by the equation below?

Sidana [21]

Answer:

We conclude that the question illustrates associative property.

6 0

3 years ago

I will mark brainliest!!

sladkih [1.3K]

Answer:

C. Events E and A are independent

Step-by-step explanation:

we will verify each options

(a)

We can use independent events formula

P(B∩C)=P(B)*P(C)

we are given

P(B)=0.4

P(C)=0.25

P(B∩C)=0.05

now, we can plug these values into formula

and we get

0.05=0.4*0.25

0.05=0.1

we can see that left side is not equal to right side

so, this is FALSE

(b)

We can use independent events formula

P(D∩A)=P(D)*P(A)

we are given

P(D)=0.25

P(A)=0.6

P(D∩A)=0.1

now, we can plug these values into formula

and we get

0.1=0.25*0.6

0.1=0.15

we can see that left side is not equal to right side

so, this is FALSE

(c)

We can use independent events formula

P(E∩A)=P(E)*P(A)

we are given

P(E)=0.5

P(A)=0.6

P(E∩A)=0.3

now, we can plug these values into formula

and we get

0.3=0.5*0.6

0.3=0.3

we can see that both sides are equal

so, this is TRUE

(d)

We can use independent events formula

P(D∩B)=P(D)*P(B)

we are given

P(D)=0.25

P(B)=0.4

P(D∩A)=0.15

now, we can plug these values into formula

and we get

0.15=0.25*0.4

0.15=0.1

we can see that left side is not equal to right side

so, this is FALSE

5 0

4 years ago