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icang [17]
3 years ago
6

Please help solve this question with steps

Mathematics
1 answer:
Orlov [11]3 years ago
8 0
39x^3 = 13*3*x*x*x

-6x^2 = 2*3*x*x*-1

-3x    = 3*x*-1

so in all these factorizations, 3*x is common. so 3x is the common factor.

by seperating the common factor,

3x(13x^2 - 2x-1)

will be the factorization.


   xy + 5x - 5y - 25

=x (y+5) -5 (y+5)
=(x-5) (y+5)

hope I helped ya!!!
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Explain how to solve a system of equations using the addition method. Use 3x - 4y=12 and 2x+y=8 to illustrate.
DerKrebs [107]

The solution to the equations 3x - 4y=12 and 2x+y=8 are x = 4 and y = 0

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have two equations:

3x - 4y=12 and

2x+y=8

Multiplu by 4 on both side in equation  2x+y=8

8x + 4y = 32

Add the equaton 8x + 4y = 32 and 3x - 4y=12

3x - 4y=12

8x + 4y = 32

11x = 44

x = 4

Similarly, we can find the value of y:

y = 0

Thus, the solution to the equations 3x - 4y=12 and 2x+y=8 are x = 4 and y = 0

Learn more about the linear equation here:

brainly.com/question/11897796

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2 years ago
Tim count his friends fingers by fives. he counts the fingers on six hands. what number does he say?
Fudgin [204]
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6 0
3 years ago
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nydimaria [60]
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3 years ago
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omeli [17]

This solution to this problem is predicated on the fact that the circumference is just: 2\pir. A straight line going through the center of the garden would actually be the diameter, which is well known to be two times the radius of the circle, so we can say that the circumference is just:

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So, solving for both the radius and the diameter gives us:

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So, the length of thes traight path that goes through the center of the guardain is just 8xy^2, and we can use the radius for the next part of the problem.

The area of a circle is \pi r^2, which means we can just plug in the radius and find our area:

A=\pi r^2 \implies \\ A=\pi (4xy^2)^2\implies \\ A= 16\pi x^2y^4

So, we have found our area(16 \pi x^2 y^4) and the problem is done.

6 0
3 years ago
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