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Alenkinab [10]
3 years ago
10

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics
2 answers:
beks73 [17]3 years ago
8 0

3\sqrt{32x^4z}=3\sqrt{32}\cdot\sqrt{x^4}\cdot\sqrt{z}\\\\=3\sqrt{16\cdot2}\cdot\sqrt{(x^2)^2}\cdot\sqrt{z}\\\\=3\sqrt{16}\cdot\sqrt2\cdot x^2\cdot\sqrt{z}\\\\\=3\cdot4\cdot\sqrt2\cdot x^2\cdot\sqrt{z}\\\\=12x^2\sqrt{2z}\\\\Used:\\\\\sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a^2}=a

Semmy [17]3 years ago
7 0
3√32x^4z

= 3√(2^5)* x^4 *z

(Square rooting the terms)

= 3*2*2*x*x√2*z

=12x^2√2z

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Answer:

Step-by-step explanation:

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The intervals are already in order from greatest to least.  Simply reverse the order to get least to greatest:

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