Well it's a dare so I guess I'll do it.
Answer:
a. a[1] = 3; a[n] = 2a[n-1]
b. a[n] = 3·2^(n-1)
c. a[15] = 49,152
Step-by-step explanation:
Each term of the given sequence is 2 times the previous term. (This description is the basis of the recursive formula.) That is, the terms of the given sequence have a common ratio of 2. This means the sequence is geometric, so the formulas for explicit and recursive rules for a geometric sequence apply.
The first term is 3, and the common ratio is 2.
<h3>(a)</h3>
The recursive rule is ...
a[1] = 3
a[n] = 2×a[n-1]
__
<h3>(b)</h3>
The explicit rule is ...
a[n] = a[1]×r^(n-1)
a[n] = 3×2^(n-1)
__
<h3>(c)</h3>
The 15th term is ...
a[15] = 3×2^(15-1) = 3×2^14
a[15] = 49,152
Answer:
Your correct answer is option C. -2 (9 + 32n)
Step-by-step explanation:
Solution:
Options are not given in the question
Given First degree expression:
-18-64n
= (-2)×9 + (-2)×32n
Take (-2) common, we get
= (-2)( 9+32n)
Therefore you get your answer of option C. -2(9+32n)
Answer:
x= -1 and x =0
Step-by-step explanation:
all work is shown and pictured
