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Slav-nsk [51]
3 years ago
7

A line has a slope of -2/3 and passes through the point -3, 8 what is the equation of the line

Mathematics
2 answers:
Aloiza [94]3 years ago
4 0
Y= -2/3 +6   bc...
(-3,8)
 y=mx+b
 8= -2/3(-3) +b
 8=2+b
-2 -2
6=b

Norma-Jean [14]3 years ago
4 0

Answer:

y=-\frac{2}{3}x+6

Step-by-step explanation:

we have been give  that

slope, m = -2/3

The line passes through the point (-3,8).

Hence, x_1=-3,y_1=8

The point slope form of a line is

y-y_1=m(x-x_1)

Substituting the known values

y-8=-\frac{2}{3}(x-(-3))

On simplifying, we get

y-8=-\frac{2}{3}x-2\\\\y=-\frac{2}{3}x+6

Thus, equation of line is y=-\frac{2}{3}x+6

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