Question

A line has a slope of -2/3 and passes through the point -3, 8 what is the equation of the line

Answer 1

Y= -2/3 +6   bc...
(-3,8)
 y=mx+b
 8= -2/3(-3) +b
 8=2+b
-2 -2
6=b

Answer 2

Answer:

$y=-\frac{2}{3}x+6$

Step-by-step explanation:

we have been give  that

slope, m = -2/3

The line passes through the point (-3,8).

Hence, $x_1=-3,y_1=8$

The point slope form of a line is

$y-y_1=m(x-x_1)$

Substituting the known values

$y-8=-\frac{2}{3}(x-(-3))$

On simplifying, we get

$y-8=-\frac{2}{3}x-2\\\\y=-\frac{2}{3}x+6$

Thus, equation of line is $y=-\frac{2}{3}x+6$