Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
Answer:oop
Step-by-step explanation:
Hello there!
(-1)^3 * (-1)^2
Use the distributive property
= (-1)(-1)(-1)* (-1)(-1)
= (-1)^5
= -1
I hope this helps!
Answer:
the answer if the first picture
Step-by-step explanation:
the second one is the explanation
