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12345 [234]
3 years ago
12

What is the output of 8

Mathematics
1 answer:
pashok25 [27]3 years ago
4 0
You should search it up.
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If the endpoints of the diameter of a circle are (6, 3) and (2, 1), what is the standard form equation of the circle?
Anastasy [175]
If the endpoints of a diameter are (6,3) and (2,1) the midpoint is the center of the circle so:

(x,y)=((6+2)/2, (3+1)/2)=(4,2)

Now we need to find the radius....the diameter is:

d^2=(6-2)^2+(3-1)^2

d^2=16+4

d^2=20  since d=2r, r=d/2, and r^2=d^2/4 so

r^2=5

The standard form of the circle is (x-h)^2+(y-k)^2=r^2 and we know:
 
(h,k)=(4,2) from earlier so:

(x-4)^2+(y-2)^2=5
8 0
3 years ago
Here are the scores for landing an arrow in the colored regions of the archery target.
Vladimir [108]

Answer:

not enough information

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Researchers for a company that manufactures batteries want to test the hypothesis that the mean battery life of their new batter
guapka [62]

(b) one-sample t-test for a population mean

ur welcome :D

8 0
3 years ago
2/4= 4-2 true or false
Degger [83]

Answer:

<h2>= Answer is false</h2>

Step-by-step explanation:

<h2>False is the ans</h2>
3 0
2 years ago
what is the distance between (0, -2) and (9, 10) ? please show your work so i can understand thank you
Setler [38]

Given:

The two points are (0, -2) and (9, 10).

To find:

The distance between the given points.

Solution:

Distance between the two points is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the above distance formula, the distance between given points is

d=\sqrt{(9-0)^2+(10-(-2))^2}

d=\sqrt{(9)^2+(10+2)^2}

d=\sqrt{81+(12)^2}

On further simplification, we get

d=\sqrt{81+144}

d=\sqrt{225}

d=15

Therefore, the distance between the given points (0,-2) and (9,10) is 15 units.

4 0
2 years ago
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