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Serga [27]
3 years ago
9

A regulation softball has a circumference of 12 inches. what is the volume of the softball?

Mathematics
1 answer:
frez [133]3 years ago
8 0
V=(4/3)pir^2

c=2pir
12=2pir
divide 2
6=pir
divide by pi
6/pi=r

sub for r
V=(4/3)pi(6/pi)^2
V=(4/3)pi(36/(pi^2))
V=(4/3)(36/pi)
V=144/(3pi)
V=48/pi
aprox pi=3.141592
V=15.2788777155

V=15.28 in^3
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Answer:

<h2>D: y= -(1/3)x -3</h2>

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<h3>One possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively</h3><h3>Other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively</h3>

<em><u>Solution:</u></em>

<em><u>The volume of rectangular pyramid is given as:</u></em>

Volume = \frac{1}{3} \times base\ area \times height

Given that,

<em><u>Rectangular pyramid has a volume of 190 cubic centimeters</u></em>

<em><u></u></em>190= \frac{1}{3} \times base\ area \times height<em><u></u></em>

<em><u>Substitute, base area = 570 and height = 1</u></em>

Then we get,

190 = \frac{1}{3} \times 570 \times 1\\\\190 = 190

Thus one possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively

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