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dem82 [27]
3 years ago
5

How do I solve 3 (9-5)² ÷8 ?

Mathematics
2 answers:
Harrizon [31]3 years ago
8 0

Answer:

3(9-5)^2 ÷8

3(4)^2÷8

3(16)÷8

3(2)=6

disa [49]3 years ago
6 0

Answer:

6

Step-by-step explanation:

9-5=4

=4

3×4^2 ÷ 8

4^2=16

3×16 ÷8

3×16=48

48÷8=6

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chubhunter [2.5K]

Answer:

The 45% off discount saves an additional $10 compared to the 15% discount for a total of $15 off regular price.

Step-by-step explanation:

We can find the original price of the game through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities. For example, we will compare percent over percent to an equal ratio  of $ to $. Since 15% of 100% is the same ratio as $5 to the unknown original $ price, I write:

\frac{15}{100} =\frac{5}{y}

I can now cross-multiply by multiplying numerator and denominator from each ratio.

15y=100(5)\\15y=500

I now solve for y by dividing by 15.

\frac{15y}{15} =\frac{500}{15} \\y= 33.33333....

The original price was $33.34.

Now, we can find the amount if 45% off and then then compare the two discounts. To find the percent off I can multiply by 0.45(33.34)=15. The 45% off discount saves an additional $10 compared to the 15% discount.

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What is the outlier for the data set?<br> 19, 19, 27, 21, 77, 18, 23, 29
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Step-by-step explanation:

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For the given function f and g, complete parts (a)-(h). For parts (a)-(d), also find the domain.
kakasveta [241]

Answer:

a) (f + g)(x) = 9x + 1

Domain: x ε R

b) (f - g)(x) = (-5x + 13)

Domain: x ε R

c) (f.g)(x) = 14x² + 37x - 42

Domain: x ε R

d) (f/g)(x) = (2x + 7)/(7x -6)

Domain: (x ε R except x = 6/7)

e) (f + g)(7) = 64

f) (f - g)(2) = 3

g) (f.g)(3) = 195

h) (f/g)(x) = 1/3

Step-by-step explanation:

f(x) = 2x + 7, g(x) = 7x - 6

a) (f + g)(x) = f(x) + g(x) = (2x + 7) + (7x - 6)

(f + g)(x) = 9x + 1

Since x is defined for functions f & g for all real numbers, the domain of (f + g)(x) is x ε R

b) (f - g)(x) = f(x) - g(x) = (2x + 7) - (7x - 6)

(f - g)(x) = (-5x + 13)

Since x is defined for functions f & g for all real numbers, the domain of (f - g)(x) is x ε R

c) (f.g)(x) = f(x) × g(x) = (2x + 7)(7x - 6)

(f.g)(x) = 14x² - 12x + 49x - 42 = 14x² + 37x - 42

Since x is defined for functions f & g for all real numbers, the domain of (f.g)(x) is x ε R

d) (f/g)(x) = f(x)/g(x) = (2x + 7)/(7x -6)

x is defined for functions f & g for all real numbers, the domain of (f/g)(x) will be x ε R except when the denominator vanishes (that is, goes to zero). This will cause the function to take up values of ∞.

This will happen when 7x - 6 = 0, x = 6/7.

Therefore, the domain of (f/g)(x) is x ε R except the point, x = 6/7.

e) (f + g)(7) = 9(7) + 1 = 64

f) (f - g)(2) = -5(2) + 13 = 3

g) (f.g)(3) = 14(3²) + 37(3) - 42 = 195

h) (f/g)(27) = (2(27) + 7)/(7(27) - 6) = 61/183 = 1/3

Hope this Helps!!!

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