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dem82 [27]
4 years ago
5

How do I solve 3 (9-5)² ÷8 ?

Mathematics
2 answers:
Harrizon [31]4 years ago
8 0

Answer:

3(9-5)^2 ÷8

3(4)^2÷8

3(16)÷8

3(2)=6

disa [49]4 years ago
6 0

Answer:

6

Step-by-step explanation:

9-5=4

=4

3×4^2 ÷ 8

4^2=16

3×16 ÷8

3×16=48

48÷8=6

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Can yall help me pls?
vlada-n [284]

Figure A maps to figure B with a scale factor of 2/3 -> Every single side of figure B equal to 2/3 of its corresponding side on triangle A.

So, we can find x by taking 10.5 x 2/3 = 7

-> x = 7

6 0
3 years ago
(04.01 MC)
levacccp [35]

9514 1404 393

Answer:

  {(0, −5), (2, 9), (−3, −26)}

Step-by-step explanation:

You only need to try the first point in each set to eliminate the wrong answers.

a: 7(-5)-5 = -40 ≠ 0

b: 7(2)-5 = 9 ≠ 7

c: 7(0)-5 = -5 . . . matches given point

d: 7(1)-5 = 2 ≠ 3

The third choice is the correct one: {(0, −5), (2, 9), (−3, −26)}.

8 0
3 years ago
What is the distance between each pair of points (-3,3),(5,0)
Effectus [21]

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the points (-3, 3) and (5, 0).

Substitute the coordinates of the points to the formula:

d=\sqrt{(5-(-3))^2+(0-3)^2}=\sqrt{8^2+(-3)^2}=\sqrt{64+9}=\sqrt{73}

7 0
4 years ago
A doctor wants to estimate the mean HDL cholesterol of all​ 20- to​ 29-year-old females. How many subjects are needed to estimat
REY [17]

(a) 404 subjects are needed to estimate the mean HDL cholesterol within 2 points with 99% confidence.

(b) When the confidence level decreases to 95%, the number of subjects decreases from 404 to 234.

<u>Explanation:</u>

Given:

σ = 15.6

Let the number of subjects be n

(a)

When the confidence level is 99%, then z = 2.576

E = 2

We know:

n = [\frac{z X s}{E}]^2

On substituting the value, we get:

n = [\frac{2.576 X 15.6}{2} ]^2\\\\n = 403.7

Thus, 404 subjects are needed to estimate the mean HDL cholesterol within 2 points with 99% confidence.

(b)

When the confidence level is 95%, then z = 1.96

E = 2

We know:

n = [\frac{z X s}{E}]^2

On substituting the value, we get:

n = [\frac{1.96 X 15.6}{2} ]^2\\\\n = 233.7

n = 234

Thus, when the confidence level decreases to 95%, the number of subjects decreases from 404 to 234.

8 0
3 years ago
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