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hammer [34]
3 years ago
5

The perimeter of the quadrilateral ABCD is 105 inches.

Mathematics
1 answer:
Oliga [24]3 years ago
7 0

Answer:

per letter like how much each letter is in incehs is 26.25 thats for each line/letter

Step-by-step explanation:

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For example( and this is straight from the paper), "15 people in 3 equal rows."
densk [106]
At a race, there are 3 rows with 15 people in each row. How many total people are there?

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(Idk if this helped very much but it's worth a shot)
6 0
3 years ago
Divide the following fractions and reduce to lowest terms 2/3 divided by 4/5
pshichka [43]
Well to divide 2 fraction you first have to find a least common number between the 2 bottom numbers in the fractions, we know automaticall that 15 fits in both the 3 and the 5. now u have to find out what to multiply by each number to get 15, for example what number do you multiply by 3 to get 15?? well it will be 5, so go ahead and multiply it by the fraction (note that what you do  in the bottom you have to do in the top) this will give you 10/15, because I multiplied the top and bottom number by 5... lets try the other one what number do you multiply by 5 to get 15?? well it will be 3 so go ahead and multiply that to get 12/15.. now add the top numbers (note that the bottoms always stay the same, you never add or subtract them) when you do you will get 22/15, now you have to see if you can simplify it any further in this case you can't so your final answer is 22/15

Hope this helps
5 0
3 years ago
Place decimal points in 431 and 205 so that the difference of the two numbers is 16.19
Gnoma [55]

Answer:

Step-by-step explanation:

Note that 20 (an approximation for 205) less 4 (an approx. for 431) comes out to 16.

This tells us that the proper placement of the decimals is

20.50

-   4.31

----------

and this comes out to 16.19.

7 0
3 years ago
during the new year celebration there are orange, green purple, and blue fireworks. In how many different orders can the differe
WINSTONCH [101]
There are 256 possible combinations of fireworks, if they can be repeated in each 4 firework combinations.
If they cannot be repeated, there are 24 possible combinations.
7 0
3 years ago
Please hurry this is Algebra 1!!!
Verdich [7]

Answer: A

256a^{20}  b^{24}

7 0
3 years ago
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