Question

Write the equation of a line that passes through the point (-1,5) and has a slope of -7 PLEASE ANSWER

Answer 1

$\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies -7 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=-7[x-(-1)]\implies y-5=-7(x+1) \\\\\\ y-5=-7x-7\implies y=-7x-2$

Answer 2

Answer: Y = -7X-2

Step-by-step explanation:

if there are two co-ordinates (x1,y1) and (x2,y2).

If the line is passing through these co-ordinates

Then Slopw of the line  = (y2-y1)/(x2-x1)

We have one co-ordinate (-1,5) let it be (X1,Y1)

Let second co-ordinate be (X,Y)

Slope = -7 = (Y-5) / (X-(-1))

-7  = (Y-5)/(X+1)

Y-5 = -7 (x+1)

Y-5 = -7x-7

ADDING 5 ON BOTH SIDES OF THE EQUATION

Y-5+5 = -7X-7+5

Y = -7x-2