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ira [324]
3 years ago
7

A box contains 8 $1’s 14 $5’s 9 $10’s 15 $20’s 2 $50’s and 7 $100’s

Mathematics
1 answer:
Serjik [45]3 years ago
5 0
The total money is $2,178
You might be interested in
The question is about trigonometry solving two sides it is a right triangle hypotenuse is X left side is 20 bottom side is 21 i
elena55 [62]

Answer:

x = 29

Angle A = 46.4°

Angle B = 43.6°

Step-by-step explanation:

Since it is a right angle triangle, we can find x from pythagoras theorem;

x = √(20² + 21²)

x = √(400 + 441)

x = √841

x = 29

Using trigonometric ratios we can find angles A and B.

Opposite is 20

Adjacent is 21

Thus; opp/adj = tan B

20/21 = tan B

B = tan^(-1) 0.9524

B = 43.6°

Sum of angles in a triangle is 180°. Thus;

A = 180 - (90 + 43.6)

A = 46.4°

4 0
2 years ago
Please helppp with this math question <333
Naya [18.7K]

Answer:

The average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

Step-by-step explanation:

We are given the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1

We need to find average rate of change.

The formula used to find average rate of change is : Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}

We have b=-1 and a=-11

Finding g(b) = g(-1)

g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9

Finding g(a) = g(-11)

g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29

Finding average rate of change

Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1

So, the average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

5 0
3 years ago
A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover
victus00 [196]

Answer:

Answer:

a. Sales from January to June: Matrix B6

                             Hard    Soft       Plastic

San Francisco     4,200   7,200     12,000

Los Angeles       2,400    1,200      3,000

b) Ending Inventory: Matrix D:

                           Hard      Soft      Plastic

San Francisco      400     4,800     3,000

Los Angeles      1,600     7,800     3,000

Step-by-step explanation:

a) Data and Calculations:

Stock on January 1: Matrix A

                              Hard    Soft       Plastic

San Francisco       1,000   3,000    6,000

Los Angeles         1,000   6,000    3,000

Sales in January: Matrix B

                             Hard    Soft       Plastic

San Francisco       700     1,200     2,000

Los Angeles         400       200        500

Restocking: Matrix C

                          Hard    Soft       Plastic

San Francisco    600   1,500      1,500

Los Angeles      500     500        500

Total Sales over the first 6 months =

Matrix B * 6 = Matrix B6

Sales in January: Matrix B

                             Hard    Soft       Plastic

San Francisco       700     1,200     2,000

Los Angeles         400       200        500

* 6

=

Sales from January to June: Matrix B6

                            Hard    Soft       Plastic

San Francisco     4,200   7,200     12,000

Los Angeles       2,400    1,200      3,000

Matrix C6 = Matrix C * 6

=

Restocking: Matrix C6

                          Hard     Soft       Plastic

San Francisco  3,600   9,000      9,000

Los Angeles    3,000   3,000      3,000

Inventory at the end of June =

Matrix A + Matrix C6 - Matrix B6

= Matrix D

Stock on January 1: Matrix A

                             Hard    Soft       Plastic

San Francisco       1,000   3,000    6,000

Los Angeles         1,000   6,000    3,000

+

Restocking: Matrix C6

                           Hard     Soft       Plastic

San Francisco  3,600   9,000      9,000

Los Angeles    3,000   3,000      3,000

-

Sales from January to June: Matrix B6

                             Hard    Soft       Plastic

San Francisco     4,200   7,200     12,000

Los Angeles       2,400    1,200      3,000

Ending Inventory: Matrix D:

                            Hard      Soft       Plastic

San Francisco      400     4,800     3,000

Los Angeles      1,600     7,800     3,000

3 0
2 years ago
Describe the change in the winning times from 2006 to 2010​
swat32
Is there any more information by any chance? Like possibly a table or chart or graph?
3 0
3 years ago
Jack and Jill live 126 km apart. They want to leave their homes at the same time,
Digiron [165]

Answer:

Both will leave their homes to meet on time at 9 am  

Step-by-step explanation:

Given as, Distance between Jack  and Jill = 126 km

Speed of Jack rides = 18 kilometers per hours

Speed of Jill rides     = 24 kilometers per hours

Let the distance travel by Jack = x km

And the distance travel by Jill  =  (126 - x ) km

Time taken by Jack and Jill = T hours

Now , Distance = Speed × Time

So,     x = 18 × T

And  126 - x = 24 × T

Or,    126 - x =  24 × \frac{x}{18}

Or,    126 - x =  x × \frac{4}{3}

Or,    378 - 3x = 4x

Or,    378 = 7x

i.e x = \frac{378}{7} = 54 km

And distance travel by Jill = 126 - 54 = 72 km

So, time taken by Jack = \frac{x}{18} = \frac{54}{18}

Or, Time taken by Jack = 3 hours

Similarly Time take by Jill = \frac{72}{24} = 3 hours

∵ Both Jack and Jill will take 3 hours to meet at 12 : 00 pm

Hence, Both will leave their homes to meet on time at 9 am   Answer

7 0
3 years ago
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