A box contains 8 $1’s 14 $5’s 9 $10’s 15 $20’s 2 $50’s and 7 $100’s

The question is about trigonometry solving two sides it is a right triangle hypotenuse is X left side is 20 bottom side is 21 i

elena55 [62]

Answer:

x = 29

Angle A = 46.4°

Angle B = 43.6°

Step-by-step explanation:

Since it is a right angle triangle, we can find x from pythagoras theorem;

x = √(20² + 21²)

x = √(400 + 441)

x = √841

x = 29

Using trigonometric ratios we can find angles A and B.

Opposite is 20

Adjacent is 21

Thus; opp/adj = tan B

20/21 = tan B

B = tan^(-1) 0.9524

B = 43.6°

Sum of angles in a triangle is 180°. Thus;

A = 180 - (90 + 43.6)

A = 46.4°

4 0

2 years ago

Please helppp with this math question <333

Naya [18.7K]

Answer:

The average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

Step-by-step explanation:

We are given the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$

We need to find average rate of change.

The formula used to find average rate of change is : $Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}$

We have b=-1 and a=-11

Finding g(b) = g(-1)

$g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9$

Finding g(a) = g(-11)

$g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29$

Finding average rate of change

$Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1$

So, the average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

5 0

3 years ago

A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover

victus00 [196]

Answer:

Answer:

a. Sales from January to June: Matrix B6

Hard Soft Plastic

San Francisco 4,200 7,200 12,000

Los Angeles 2,400 1,200 3,000

b) Ending Inventory: Matrix D:

Hard Soft Plastic

San Francisco 400 4,800 3,000

Los Angeles 1,600 7,800 3,000

Step-by-step explanation:

a) Data and Calculations:

Stock on January 1: Matrix A

Hard Soft Plastic

San Francisco 1,000 3,000 6,000

Los Angeles 1,000 6,000 3,000

Sales in January: Matrix B

Hard Soft Plastic

San Francisco 700 1,200 2,000

Los Angeles 400 200 500

Restocking: Matrix C

Hard Soft Plastic

San Francisco 600 1,500 1,500

Los Angeles 500 500 500

Total Sales over the first 6 months =

Matrix B * 6 = Matrix B6

Sales in January: Matrix B

Hard Soft Plastic

San Francisco 700 1,200 2,000

Los Angeles 400 200 500

* 6

=

Sales from January to June: Matrix B6

Hard Soft Plastic

San Francisco 4,200 7,200 12,000

Los Angeles 2,400 1,200 3,000

Matrix C6 = Matrix C * 6

=

Restocking: Matrix C6

Hard Soft Plastic

San Francisco 3,600 9,000 9,000

Los Angeles 3,000 3,000 3,000

Inventory at the end of June =

Matrix A + Matrix C6 - Matrix B6

= Matrix D

Stock on January 1: Matrix A

Hard Soft Plastic

San Francisco 1,000 3,000 6,000

Los Angeles 1,000 6,000 3,000

+

Restocking: Matrix C6

Hard Soft Plastic

San Francisco 3,600 9,000 9,000

Los Angeles 3,000 3,000 3,000

-

Sales from January to June: Matrix B6

Hard Soft Plastic

San Francisco 4,200 7,200 12,000

Los Angeles 2,400 1,200 3,000

Ending Inventory: Matrix D:

Hard Soft Plastic

San Francisco 400 4,800 3,000

Los Angeles 1,600 7,800 3,000

3 0

2 years ago

Describe the change in the winning times from 2006 to 2010

swat32

Is there any more information by any chance? Like possibly a table or chart or graph?

3 0

3 years ago

Jack and Jill live 126 km apart. They want to leave their homes at the same time,

Digiron [165]

Answer:

Both will leave their homes to meet on time at 9 am

Step-by-step explanation:

Given as, Distance between Jack and Jill = 126 km

Speed of Jack rides = 18 kilometers per hours

Speed of Jill rides = 24 kilometers per hours

Let the distance travel by Jack = x km

And the distance travel by Jill = (126 - x ) km

Time taken by Jack and Jill = T hours

Now , Distance = Speed × Time

So, x = 18 × T

And 126 - x = 24 × T

Or, 126 - x = 24 × $\frac{x}{18}$

Or, 126 - x = x × $\frac{4}{3}$

Or, 378 - 3x = 4x

Or, 378 = 7x

i.e x = $\frac{378}{7}$ = 54 km

And distance travel by Jill = 126 - 54 = 72 km

So, time taken by Jack = $\frac{x}{18}$ = $\frac{54}{18}$

Or, Time taken by Jack = 3 hours

Similarly Time take by Jill = $\frac{72}{24}$ = 3 hours

∵ Both Jack and Jill will take 3 hours to meet at 12 : 00 pm

Hence, Both will leave their homes to meet on time at 9 am Answer

7 0

3 years ago