Answer:
The average acceleration of the cyclist was 0.6 m/s².
Step-by-step explanation:
Acceleration:
The rate change of velocity per unit time is call the acceleration of the object.
![a=\frac{v-u}t](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv-u%7Dt)
u= initial velocity
v= final velocity
t= time taken change of velocity.
During the final 5 seconds of a race cyclist increased her velocity from 4m/s to 7 m/s
Here v= 7 m/s and u=4 m/s t=5 seconds
![\therefore a=\frac{7\ m/s-4 \ m/s}{5s}](https://tex.z-dn.net/?f=%5Ctherefore%20a%3D%5Cfrac%7B7%5C%20m%2Fs-4%20%5C%20m%2Fs%7D%7B5s%7D)
![=\frac{3}{5} \ m/s^2](https://tex.z-dn.net/?f=%3D%5Cfrac%7B3%7D%7B5%7D%20%5C%20m%2Fs%5E2)
=0.6 m/s²
The average acceleration of the cyclist was 0.6 m/s².
Answer:
42
Step-by-step explanation:
(7)x6
42
For this case we have the following expressions:
![2b + b\\3b](https://tex.z-dn.net/?f=2b%20%2B%20b%5C%5C3b)
For ![b = 1:](https://tex.z-dn.net/?f=b%20%3D%201%3A)
![2 (1) + 1 = 2 + 1 = 3\\3 (1) = 3](https://tex.z-dn.net/?f=2%20%281%29%20%2B%201%20%3D%202%20%2B%201%20%3D%203%5C%5C3%20%281%29%20%3D%203)
For ![b = 2:](https://tex.z-dn.net/?f=b%20%3D%202%3A)
![2 (2) + 2 = 4 + 2 = 6\\3 (2) = 6](https://tex.z-dn.net/?f=2%20%282%29%20%2B%202%20%3D%204%20%2B%202%20%3D%206%5C%5C3%20%282%29%20%3D%206)
For
:
![2 (3) + 3 = 6 + 3 = 9\\3 (3) = 9](https://tex.z-dn.net/?f=2%20%283%29%20%2B%203%20%3D%206%20%2B%203%20%3D%209%5C%5C3%20%283%29%20%3D%209)
For any number, the expressions will be equivalent because ![2b + b = 3b](https://tex.z-dn.net/?f=2b%20%2B%20b%20%3D%203b)
ANswer:
and
have the same value for b = 1,2,3
Answer:
Adam is 9 years old.
Step-by-step explanation:
Let d and c represent Adam's and Alicia's ages.
d = c - 15, and
c + 6 = 2(d + 6)
Rearrange d = c - 15 as c = d + 15, and then substitute d + 15 for c in the second equation. We obtain:
d + 15 + 6 = 2(d + 6), or
d + 21 = 2d + 12
Combining like terms, we get 21 = d + 12, or 9 = d.
If d = 9 then c = d + 15, or c = 9 + 15, or c = 24.
Adam is 9 years old.
Answer:
Step-by-step explanation:
Given that a contractor records the areas, in square feet, of several houses in a neighborhood to determine data about the neighborhood.
Let X1, X2,...Xn be the data set
We find mean of this by the formula sum/n
Mean = ![\bar x =\frac{x_1+x_2+x_3+..+x_n}{n}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%5Cfrac%7Bx_1%2Bx_2%2Bx_3%2B..%2Bx_n%7D%7Bn%7D)
Now variance is calculated as sum of squares of deviations of each entry from this mean.
Var(x) = ![\frac{1}{n} \Sigma _{i=1} ^n(x_i-\bar x)^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bn%7D%20%20%5CSigma%20_%7Bi%3D1%7D%20%5En%28x_i-%5Cbar%20x%29%5E2)
Standard deviation = square root of variance
Thus first mean, then variance then sd deviation is calculated.