Let's solve this problem step-by-step.
First of all, let's establish that supplementary angles are two angles which add up to 180°.
Therefore:
Equation No. 1 -
x + y = 180°
After reading the problem, we can convert it into an equation as displayed as the following:
Equation No. 2 -
3x - 8 + x = 180°
Now let's make (y) the subject in the first equation as it is only possible for (x) to be the subject in the second equation. The working out is displayed below:
Equation No. 1 -
x + y = 180°
y = 180 - x
Then, let's make (x) the subject in the second equation & solve as displayed below:
Equation No. 2 -
3x - 8 + x = 180°
4x = 180 + 8
x = 188 / 4
x = 47°
After that, substitute the value of (x) from the second equation into the first equation to obtain the value of the other angle as displayed below:
y = 180 - x
y = 180 - ( 47 )
y = 133°
We are now able to establish that the value of the two angles are as follows:
x = 47°
y = 133°
In order to determine the measure of the bigger angle, we will need to identify which of the angles is larger.
133 is greater than 47 as displayed below:
133 > 47
Therefore, the measure of the larger angle is 133°.
<span> 80/-40=-40/20=-2,
the sequence: 80, -40, 20 is a geometric sequence
its general formula is Vn+1 = q Vn, where q= -2,
if we put </span>Vn+1 = f(x)
<span> Vn = x
so we have f(x)= -2x so the graph that represents the sequence is graph of linear equation
</span>
For #7 - part a: greatest common factor (GCF) is 5.
Part b: cross out everything BUT 10 & 20.
Answer:
64 teachers
Step-by-step explanation:
We can use ratios to solve
14 students 896 students
----------------- = -------------
1 teacher x teachers
Using cross products
14 * x = 896*1
Divide each side by 14
14x/14 = 896/14
x =64
