Simple pythagorus theorem with the equation a^2=b^2+c^2
To find AC, (2^2)+(3^2)=4+9=13
AC=the square root of 13
Answer:
1.
Vert. asymptote: x = {-3, 2}
Horiz. asymptote: y = 0
x-int: None
Question 3.
a. There is no hole
b. Vert. asymptote: x = {-2, 2}
c. f(x) = 0: x = {0, -1/2}
d. The graph has no hole at (-2, 4)
Question 4.
a. Vert. asymptote: x = {-2, 2}
b. f(x) = 0: x = {0, -1/2}
c. Horizontal asymptote: y = 2
d. The graph has no hole
I'm a bit confused. Some of the things stated in the question aren't true like how there are holes in places where there aren't.
Answer:
x= 62
y= 54
Step-by-step explanation:
Step one:
given data
let the numbers be x and y and the larger be x the smaller be y
The difference between two numbers is 8
x-y= 8-----------1
If the larger is subtracted from three times the smaller, the difference is 100
3y-x=100------------2
from eqn 1, x= 8+y
put this in eqn 2
3y-(8+y)=100
3y-8-y=100
collect liker terms
3y-y-8=100
2y=108
y= 54
put y= 54 in eqn 1
x-y=8
x-54= 8
x= 8+54
x=62
Answer:
Step-by-step explanation:
Let's start by using change of base property:
So, for 
Now, using change of base for 
You can express 
as:
Using reduction of power property:
Therefore:
As you can see the only difference between (1) and (2) is the coefficient 
:
So:
31/7 = 4 3/7.....3/7 is less then 1/2....so the closest integer is 4
